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Al (neutral atom) is 1s2 2s2 2p6 3s2 3p1, so if it loses 2 electrons to become Al^2+ wouldn't make much sense, as it wants to lose 3 electrons to become Al^3+ which will then be isoelectronic with Neon. Are you sure you meant Al^2+ and not Al^3+. If you meant Al^2+, the it will be 1s2 2s2 2p6 3s1 (not likely, however).

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7y ago

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