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What is the volume occupied by 450 g of gold if the density of gold is 19. g per cm3?
The volume of gold can be calculated by dividing the mass by the density. In this case, 450 g divided by 19 g/cm^3 gives a volume of 23.68 cm^3. Therefore, 450 g of gold occupies a volume of 23.68 cm^3.
If the mass density of gold is 193gramscubic centimeter and you were gave 15 kilograms of gold what is the volume?
To find the volume of gold, first convert the mass of gold to grams (1 kg = 1000 g), so 15 kg = 15000 g. Then, use the mass density formula: density = mass/volume, rearrange it to find volume: volume = mass/density. Plug in the values: volume = 15000 g / 19.3 g/cm^3 = 777.2 cubic centimeters.
How much volume will 180.0 g of gold occupy?
The volume of a substance can be calculated using its density. The density of gold is approximately 19.3 g/cm³. Using the formula: Volume = Mass / Density Volume = 180 g / 19.3 g/cm³ Volume ≈ 9.33 cm³ Therefore, 180.0 g of gold will occupy approximately 9.33 cm³.
What is the volume of a 75 gram sample of gold at STP?
The density of gold is 19.32 g/cm^3. To find the volume of a 75 gram sample of gold, you divide the mass by the density: 75 g / 19.32 g/cm^3 ≈ 3.88 cm^3.
What is the density of a gold nugget that has a volume of 1.68 cm3 and a mass of 32.4 g?
With the information given, the density of your nugget is about 19.29 g/cc. The density of gold is given as about 19.3 g/cc, so your nugget fits the density requirements for it to be a gold nugget.
What is the volume of a 2 g piece of gold?
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a piece of gold has a mass of 9.66 g. what is its volume?
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What is the volume occupied by 450 g of gold if the density of gold is 19. g per cm3?
The volume of gold can be calculated by dividing the mass by the density. In this case, 450 g divided by 19 g/cm^3 gives a volume of 23.68 cm^3. Therefore, 450 g of gold occupies a volume of 23.68 cm^3.
What is the volume of 95g of gold?
To find the volume of 95 grams of gold, you can use the formula: volume = mass/density. The density of gold is approximately 19.32 grams per cubic centimeter (g/cm³). Thus, the volume of 95 grams of gold would be 95 g ÷ 19.32 g/cm³, which is about 4.91 cm³.
What is the volume of a piece of magnesium that weighs 2.70 g?
The volume is 1.55 cm^3.
If pure gold has a density of 19.32 gcm3. How large would of gold be if it had a mass of 318.97 g?
The volume of the gold can be calculated using the formula: Volume = Mass / Density. Substituting the given values, Volume = 318.97 g / 19.32 g/cm^3 = 16.52 cm^3. So, the gold would have a volume of 16.52 cm^3.
If the mass density of gold is 193gramscubic centimeter and you were gave 15 kilograms of gold what is the volume?
To find the volume of gold, first convert the mass of gold to grams (1 kg = 1000 g), so 15 kg = 15000 g. Then, use the mass density formula: density = mass/volume, rearrange it to find volume: volume = mass/density. Plug in the values: volume = 15000 g / 19.3 g/cm^3 = 777.2 cubic centimeters.
Is the volume of gold 20g greater than the volume of lead 10g?
We need to calculate the volume of a metal from the density to be sure. Density of pure gold = 19.3  g·cm-3Density of pure lead = 11.34  g·cm-3The volume of 20 g of gold = mass/density = 20 [g] / 19.3  g·cm-3 = 1.036 cm3 The volume of 10 g of lead = mass/density = 10 [g] / 11.34  g·cm-3 = 0.882 cm3 Hence, the volume of 20 g of gold is slightly greater than that of 10 g of lead. =========================
The density of gold is 19.3 g cm3 The density of iron pyrite is 5.0 g cm3 If a nugget of iron pyrite and a nugget of gold each have a mass of 50 g what can you conclude about the volume of each nugget?
The nugget of gold has a volume of 2.6 cm3, and the nugget of pyrite has a volume of 10 cm3.
What is the density of a piece that has a mass of 210 g and a volume of 20.0 cm cubed?
The density of the piece is 10.5 g/cm^3. This is calculated by dividing the mass (210 g) by the volume (20.0 cm^3). Density is a measure of how much mass is contained in a given volume.
Find the density of a piece of paper that has a mass of 15.5 g and a volume of 27.0 cm3?
The density of the piece of paper is calculated by dividing its mass (15.5 g) by its volume (27.0 cm3). Density = mass/volume = 15.5 g / 27.0 cm3 = 0.574 g/cm3.
How much volume will 180.0 g of gold occupy?
The volume of a substance can be calculated using its density. The density of gold is approximately 19.3 g/cm³. Using the formula: Volume = Mass / Density Volume = 180 g / 19.3 g/cm³ Volume ≈ 9.33 cm³ Therefore, 180.0 g of gold will occupy approximately 9.33 cm³.
