3.9 cm3 (cubed)
The gram molecular volume of ozone at STP (standard temperature and pressure) is approximately 22.4 L/mol.
To find the volume of the acetylene gas at STP, we can use the ideal gas law equation: PV = nRT. First, we must convert the given mass of acetylene gas to moles using its molar mass. Then, knowing STP conditions (standard temperature = 273 K and standard pressure = 1 atm), we can calculate the volume.
To calculate the volume of CO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. First, find the number of moles of CO2 using the ideal gas law equation. Then, use the molar volume of a gas at STP (22.4 L/mol) to find the volume at STP.
The gas sample that has the greatest number of molecules is the one with the largest amount of substance, which is measured in moles. At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. Therefore, the gas sample with the largest volume at STP will have the greatest number of molecules.
Gold is a solid at standard temperature and pressure (STP).
The gram molecular volume of ozone at STP (standard temperature and pressure) is approximately 22.4 L/mol.
5600 mL
To find the volume of the acetylene gas at STP, we can use the ideal gas law equation: PV = nRT. First, we must convert the given mass of acetylene gas to moles using its molar mass. Then, knowing STP conditions (standard temperature = 273 K and standard pressure = 1 atm), we can calculate the volume.
To calculate the volume of CO2 at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT. First, find the number of moles of CO2 using the ideal gas law equation. Then, use the molar volume of a gas at STP (22.4 L/mol) to find the volume at STP.
Gold is a solid at standard temperature and pressure (STP).
The gas sample that has the greatest number of molecules is the one with the largest amount of substance, which is measured in moles. At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. Therefore, the gas sample with the largest volume at STP will have the greatest number of molecules.
Using the ideal gas law equation, we can calculate the new volume of the gas. At STP, the pressure is 1 atm, which means 50 atm is 50 times greater. So the new volume would be 1.55L / 50 = 0.031L, when the pressure is increased to 50 atm.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L
The volume of 10.9 mol of helium at STP is 50 litres.
At standard temperature and pressure (STP), the gas that occupies the highest volume is hydrogen.
The volume of 35.7 grams of water = 35.7 cubic centimetres at standard temperature and pressure, (STP). This means a sample at 0°C at a pressure of one atmosphere.