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CuCO3 + H2SO4 -> CuSO4 + H2O + CO2
copper(II) carbonate + sulphuric acid -> copper(II) sulphate water + carbon dioxide
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∙ 12y ago
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∙ 14y agoThis is how all caves are formed the only cave that does not use this formula is the granite caves sometimes found in the USA
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∙ 14y agoCuO3 + H2SO4 --> CuSO4 + H2O + CO2
cupric oxide and sulfuric acid become cupric sulfate, water, and carbon dioxide.
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∙ 13y agoCarbon dioxide plus water equals carbonic acid.
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∙ 8y agoThe reaction is:
Ca(OH)2 + CO2 = CaCO3 + H2O
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∙ 7y agoThe chemical equation is: CuO + H2SO4 = CuSO4 + H2O
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∙ 12y agodouble replacement
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∙ 11y ago2Cu2S + 2O2 ----> 2Cu2O + SO2
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∙ 7y agoCuO plus H2SO4 --> H2O + CuSO4
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How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
Equation for when copper oxide reacts with sulfuric acid?
CuO + H2SO4 --> CuSO4 + H2O
What is the formula for copper oxide and hydrogen sulphate?
copper oxide- CuO hydrogen sulphate- h2SO4
What is the balanced equation for the reaction between copper oxide and sulfuric acid?
CuO + H2SO4 --> CuSO4 + H2O
Why does fizzing occur in a reaction between copper ii oxide and sulphuric acid?
The chemical formula for copper (ii) oxide is CuO The chemical formula for Sulphuric acid is H2SO4. So a chemical reaction between them would look like this: CuO + H2SO4 -> CuSO4 + H2O
How many milliliters of 3.0 m h2so4 are required to react with 0.80 g of cuo in the equation cuo h2so4 cuso4 H2O?
We need to go from grams of CuO to mL of H2SO4. Atomic weight of CuO = 63.55 g Cu + 16 g O = 79.55 g CuO (.80 g CuO) * (1 mol CuO / 79.55 g CuO) = .0100566 mol CuO (g CuO cancel) Since the moles of CuO is a 1:1 ratio to H2SO4 (see balanced equation) we know that: mol CuO = mol H2SO4 or 0.0100566 mol CuO = 0.0100566 mol H2SO4 3.0 M of H2SO4 means that there is 3 mol / 1 L. So we can divide this by the moles to get L then mL of H2SO4 (0.0100566 mol H2SO4) * (1 L H2SO4 / 3 mol H2SO4) * (1000 mL H2SO4 / 1 L H2SO4) = 3.4 mL H2SO4 (mol H2SO4 and L H2SO4 cancel) So 3.4 ml of H2SO4 is needed to react with 0.80 g of CuO.
How do you chemically make copper sulphate?
Copper (II) sulphate, CuSO4 is prepared by mixing copper (II) oxide, CuO with sulfuric acid, H2SO4. CuO + H2SO4 --> CuSO4 + H2O
Equation for when copper oxide reacts with sulfuric acid?
CuO + H2SO4 --> CuSO4 + H2O
CuO plus HCL-CuCl2 plus H2O?
CuO + 2HCL - CuCl2 + H2O
What is the formula for copper oxide and hydrogen sulphate?
copper oxide- CuO hydrogen sulphate- h2SO4
Is Cu oxidized or reduced in CuO plus H2 yields Cu plus H2O?
Cu is oxidized. The oxidation number goes from 0 in Cu to +2 in CuSO4. S is reduced. The oxidation number goes from +6 in H2SO4 to +4 in SO2. The oxidizing agent is H2SO4 since it causes Cu to be oxidized. The reducing agent is Cu since it causes S in H2SO4 to be reduced.
What is the balanced equation for the reaction between copper oxide and sulfuric acid?
CuO + H2SO4 --> CuSO4 + H2O
Why does fizzing occur in a reaction between copper ii oxide and sulphuric acid?
The chemical formula for copper (ii) oxide is CuO The chemical formula for Sulphuric acid is H2SO4. So a chemical reaction between them would look like this: CuO + H2SO4 -> CuSO4 + H2O
What is the symbol equation for copper carbonate plus sulphuric acid to copper sulphate plus water plus carbon dioxide?
Copper carbonate + sulphuric acid = copper sulphate + water + carbon dioxide
What do you get from Fe plus CuO?
2 Fe + 3 CuO -> Fe2O3 + 3 Cu
What do you get if you mix copper oxide and sulfuric acid?
water and copper(II)sulfate CuO + H2SO4 --> CuSO4 + H2O
What happens when dilute sulphuric acid is added to copper oxide?
CuO + H2SO4 -> CuSO4 + H2O copper sulfate and water produced
