Is this the reaction you mean 2Br Cl2--->Br2 2Cl This can be happen.Equation in your question cannot be happened
When chromium bromide is put into water, it dissociates into ions. The reaction is: CrBr2(s) → Cr2+(aq) + 2Br-(aq).
In the reaction between MnBr2 and Na2SO3 a precipitate (insoluble) compound is formed, and that is MnSO3. So, the net ionic equation is Mn^2+(aq) + SO3^2-(aq) ==> MnSO3(s). The other ions (2Na^2+ and 2Br^-) are spectator ions.
The complete ionic formula for the reaction between Ca(NO3)2 and NH4Br is: Ca^2+ + 2NO3^- + 2NH4+ + 2Br^- -> Ca(NO3)2 + 2NH4Br
The ionic equation is 2K+(aq) + 2OH-(aq) + Co^2(aq) + 2Br^-(aq) ==> 2K+(aq) + 2Br-(aq) + Co(OH)2(s)net ionic equation is Co2+(aq) + 2OH-(aq) ==> Co(OH)2(s)So spectators are K+ and Br- ions.
When aqueous bromide ions react with chlorine gas, bromide ions are oxidized to form bromine gas. This reaction typically occurs in the presence of an acid as a catalyst. The overall reaction can be represented by the equation: 2Br^-(aq) + Cl2(g) -> Br2(g) + 2Cl^-(aq)
Bromine is the oxidizing element.
S in (SO4)-2 has a charge of +6, in SO2 S has a charge of +4. To go from +6 to +4 you must gain two electrons. The (SO4)-2 is reduced (reduction is gaining electrons). Therefore it reduces the 2br-, so (SO4)-2 is the reducing agent
When liquid bromine is shaken with a sodium iodide solution, a redox reaction occurs between the bromine and iodide ions. This reaction results in the formation of brown iodine molecules. The overall reaction can be represented as Br2 + 2NaI → 2NaBr + I2.
The bromine oxidizes iodide ions to produce iodine and bromide ions. The overall reaction is 2I- + Br2 → I2 + 2Br-.
The net ionic equation for barium hydroxide (Ba(OH)2) plus hydrobromic acid (HBr) is Ba(OH)2 + 2H+ + 2Br- -> Ba2+ + 2Br- + 2H2O. This equation highlights the formation of barium ions (Ba2+) and water molecules (H2O) as the only significant species in the reaction.
6.3 x 10-6
When chromium bromide is put into water, it dissociates into ions. The reaction is: CrBr2(s) → Cr2+(aq) + 2Br-(aq).
That no matter is lost during the reaction. That is why the number of atoms of a specific element on one side of the reaction is equal to the number of atoms on the other side. Na2S + 2HBr -------> 2NaBr + H2S #of atoms................ #of atoms 2Na..............................2Na 1S................................1S 2H............................... 2H 2Br.............................. 2Br
In the reaction between MnBr2 and Na2SO3 a precipitate (insoluble) compound is formed, and that is MnSO3. So, the net ionic equation is Mn^2+(aq) + SO3^2-(aq) ==> MnSO3(s). The other ions (2Na^2+ and 2Br^-) are spectator ions.
The balanced chemical equation for the reaction between chlorine (Cl2) and bromine (Br2) is: Cl2 + Br2 -> 2ClBr
The complete ionic formula for the reaction between Ca(NO3)2 and NH4Br is: Ca^2+ + 2NO3^- + 2NH4+ + 2Br^- -> Ca(NO3)2 + 2NH4Br
The reaction of iron(II) salts with bromine is a redox reaction forming iron(III). The aqueous reaction with bromine water is typical:- 2Fe2+ + Br2 -> 2Fe3+ + 2Br- If you started with iron(II) bromide, iron(III) bromide would be formed