An endothermic reaction, because it uses heat. If it gave off heat it would be exothermic.
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
The reaction is:CH3NH2 + HBr = CH3NH3Br
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
The conjugate acid in the reaction is H3O+. It is formed when HBr donates a proton (H+) to water, resulting in the formation of the hydronium ion (H3O+).
HBr + NaOH ------> NaBr + H2O This is an acid-base reaction. The compounds will disassociate into ions in solution. The hydrogen from the HBr will go to the OH- and form water. The NaBr is a salt.
To balance the reaction HBr + B → BBr3 + H2, we consider the number of atoms of each element on both sides. The balanced reaction is 6 HBr + 2 B → 2 BBr3 + 3 H2. Thus, the two substances that would have a coefficient of 2 in the balanced equation are BBr3 and H2.
The reaction of 2Br2 + 2H2O → 4HBr + O2 involves the oxidation of bromine (Br2) by water (H2O) to form hydrogen bromide (HBr) and oxygen (O2). Bromine is reduced to HBr, and oxygen gas is released as a byproduct.
The reaction is:CH3NH2 + HBr = CH3NH3Br
The equation represents the reaction between methane (CH4) and bromine (Br2) to form methyl bromide (CH3Br) and hydrogen bromide (HBr). This reaction is a substitution reaction in which a hydrogen atom in methane is replaced by a bromine atom.
This is a Neutralization reaction. HBr(aq)+CsOH(aq)--->CsBr(aq)+H2O(l)
Al2O3 + 6HBr = 2Albr3 + 3H2O
In the reaction, HBr donates a proton (H+) to H2O, making HBr the acid and H2O the base. The resulting products are Br- (conjugate base of HBr) and H3O+ (conjugate acid of H2O).
This equation is:HBr + LiOH = LiBr + H2O
When bromine reacts with water, it forms hydrobromic acid (HBr) and hypobromous acid (HOBr). The overall reaction can be represented as: Br2 + H2O → HBr + HOBr. This reaction is reversible and depends on the pH and conditions of the solution.
None. This is a metathesis reaction, and thus nothing is produced but a combination of the reactants (NH4Br, for example).