This is a double replacement reaction which forms barium sulfate and salt (NaCl) when the sodium ions in sodium sulfate (mirabilite) remove chlorine from barium chloride.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
The balanced reaction is: 2Cl + 2KI → 2KCl + I2. It is balanced by ensuring there are the same number of each type of atom on both sides of the reaction arrow.
The reaction between 2 moles of potassium (K) and 1 mole of iodine (I2) to form 2 moles of potassium iodide (KI) is a combination or synthesis reaction. In this reaction, two elements are reacting to form a single compound.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
The given reaction is an example of "synthesis" reaction, in particular one in which two elements react to form a chemical compound.
The reaction between potassium iodide (KI) and dilute sulfuric acid (H2SO4) can be represented by the following equation: 2KI + H2SO4 -> 2KHSO4 + HI
Chlorine gas reacts with potassium iodide to produce potassium chloride and iodine. This reaction can be represented by the chemical equation: Cl2 + 2KI -> 2KCl + I2.
The balanced reaction is: 2Cl + 2KI → 2KCl + I2. It is balanced by ensuring there are the same number of each type of atom on both sides of the reaction arrow.
The reaction between 2 moles of potassium (K) and 1 mole of iodine (I2) to form 2 moles of potassium iodide (KI) is a combination or synthesis reaction. In this reaction, two elements are reacting to form a single compound.
This is a double displacement reaction, also known as a metathesis reaction. In this reaction, the chlorine atoms in Cl2 and the iodide ions in KI swap partners to form potassium chloride (KCl) and iodine (I2).
The given reaction is an example of "synthesis" reaction, in particular one in which two elements react to form a chemical compound.
When iodide is mixed with silver nitrate, a yellow precipitate of silver iodide is formed due to a double displacement reaction. This reaction can be represented by the chemical equation: 2AgNO3 + 2KI → 2AgI + 2KNO3.
To balance the reaction Cl2 + KI -> KCl + I2, you just need to place a coefficient of 2 in front of KCl to balance the number of chlorine atoms on both sides of the reaction. The balanced reaction is Cl2 + 2KI -> 2KCl + I2.
2KI + Cl2 = 2KCl + I2
The balanced equation for the reaction would be: 2ClO + 2HCl + C6H10O5 + 2KI → 2KCl + 2H2O + CO2 + I2.
The displacement reaction between potassium chloride and iodine solution can be represented by the equation: 2KCl(aq) + I2(aq) -> 2KI(aq) + Cl2(g)
When Pb(NO3)2 (lead nitrate) is mixed with KI (potassium iodide), a yellow precipitate of lead iodide (PbI2) is formed. This reaction can be represented by the equation: Pb(NO3)2 + 2KI -> 2KNO3 + PbI2.