answersLogoWhite

0


Best Answer

1. Weigh 21,256 g ultrapure LiOH dried at 110 0C for 30 min.
2. Transfer LiOH in a clean 1 L volumetric flask using a funnel. 3. Wash the funnel with 0,9 L demineralized water.
4. Put the flask in a thermostat and maintain 30 min at 20 0C.
5. Add demineralized water up to the mark.
6. Stir vigorously and transfer in a clean bottle with stopper.
7. Add a label with necessary information.

User Avatar

Wiki User

6y ago
This answer is:
User Avatar
More answers
User Avatar

Wiki User

6y ago

molar mass LiOH = 23.95 g/mol3.55 mol/L x 0.250 L x 23.95 g/mole = 21.25 g = 21.3 g (to 3 significant figures) = mass needed.


This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What mass of LiOH is required to prepare 0.250 L of a 3.55 M solution?
Write your answer...
Submit
Still have questions?
magnify glass
imp