5.85 g
We have to use Q = m s @
Q - heat energy in joule ie 65.5 J
s - specific heat capacity ie 0.140 J/g/C
@ = @2 - @1 = 100 - 20 = 80 C
Just plug and you get the above 5.85 g nearly
Add:
Q = m•C•Δt, where Q is heat added, m is mass in grams, C is specific heat, and Δt is change in temperature.
Known:
Q = 65.5 Joules
C = 0.140 J/g•oC
Δt = 100oC-20oC = 80oC
Unknown: mass of Mercury in grams
Solution
m = Q/C•Δt
m = 65.5 J/(0.140 J/g•oC)(80oC) = 6 grams (rounded to 1 significant figure)
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It is the Specific Heat Capacity.
The Energy
Specific heat
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