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5.85 g

We have to use Q = m s @

Q - heat energy in joule ie 65.5 J

s - specific heat capacity ie 0.140 J/g/C

@ = @2 - @1 = 100 - 20 = 80 C

Just plug and you get the above 5.85 g nearly

Add:

Q = m•C•Δt, where Q is heat added, m is mass in grams, C is specific heat, and Δt is change in temperature.

Known:

Q = 65.5 Joules

C = 0.140 J/g•oC

Δt = 100oC-20oC = 80oC

Unknown: mass of Mercury in grams

Solution

m = Q/C•Δt

m = 65.5 J/(0.140 J/g•oC)(80oC) = 6 grams (rounded to 1 significant figure)

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