What mass of sucrose C12H22O11 is needed to make 500 ...
For this you need the atomic (molecular) mass of C12H22O11. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. C12H22O11= 342 grams.105 moles C12H22O11 × (342 grams)= 35.9 grams C12H22O11
It depends upon how much you have, but its molar mass is about 342g/mol, meaning 1 mole of table sugar (sucrose, C12H22O11) has a mass equal to the sum of all the molecule's constituent elements.
Since magnesium and helium do not form elemental molecules, a mole of these elements is the same as a gram atomic mass, which is 24.305 for magnesium and 4.00260 for helium. The gram molecular mass for sucrose is 342.30. Therefore, the mass of: A. 3 moles of magnesium is 72.915 grams; B 1 mole of sucrose (C12H22O11) is 342.30 grams; and C. 10 moles of helium is 40.0260 grams. The largest of these is obviously the single mole of sucrose.
The molecular mass of Sucrose C12H22O11 is 342 a.m.u, so simply dissolve 342g sucrose in water to make the solution 1dm3.
Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M
For this you need the atomic (molecular) mass of C12H22O11. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel. C12H22O11= 342 grams.105 moles C12H22O11 × (342 grams)= 35.9 grams C12H22O11
You divide 7.08ee10^20/6.022ee^23 = .0011756891 then you times that number by the grams of sucrose(C12H22O11) .0011756891 X 342 = .402g of C12H22O11
It depends on the kind of sugar you are talking about. If you are talking about glucose or fructose, the molecular formula is C6H12O6 (glucose and fructose only differ in structure but have the same formula). Sucrose, which is common table sugar, has the molecular formula C12H22O11. Scientifically, the word "sugar" is used for any mono- or di-saccharide. Sugar added in food is called sucrose. Sugar naturally found in fruit is called fructose.
It depends upon how much you have, but its molar mass is about 342g/mol, meaning 1 mole of table sugar (sucrose, C12H22O11) has a mass equal to the sum of all the molecule's constituent elements.
Since magnesium and helium do not form elemental molecules, a mole of these elements is the same as a gram atomic mass, which is 24.305 for magnesium and 4.00260 for helium. The gram molecular mass for sucrose is 342.30. Therefore, the mass of: A. 3 moles of magnesium is 72.915 grams; B 1 mole of sucrose (C12H22O11) is 342.30 grams; and C. 10 moles of helium is 40.0260 grams. The largest of these is obviously the single mole of sucrose.
The molecular mass of Sucrose C12H22O11 is 342 a.m.u, so simply dissolve 342g sucrose in water to make the solution 1dm3.
1 litre is 1000ml therefore 15g per 100ml would equal 150g per 1000ml. So 3 Litres would contain 450g.
Total sugar content is percentage by mass of sucrose (saccharose, C12H22O11, molecular mass 342 g/mol)Invert sugar content is percentage by mass of the glucose (C6H12O6, molecular mass 180 g/mol) and fructose (also C6H12O6, molecular mass 180 g/mol) mixture produced from saccharose (C12H22O11) and water (H2O) by 'invertase' reaction:saccharose (C12H22O11) + H2O --> glucose (C6H12O6) + fructose (C6H12O6)Through this reaction the mass of total sugar increases 18 g (by 'addition' of water to the molecular formulae) per mole (342g) of sucrose. This is about 5% increase in mass and concentration value.The total molarity is doubled, the sweetness also increased (about 20-30%) after inversion reaction.
The formula for sucrose is C11H22O11. To figure this out, you need to list the elements in the compound along with the amount of times it is in the compound and the atomic masses of the elements, like so... Carbon 11 12 132 Hydrogen 22 1 22 Oxygen 11 16 176 Add the right column all up and you get 330. So, to reiterate, sucrose has a molar mass of 330 to the nearest gram.
Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M Molarity (M) represents the moles of a solute per liter of a solvent. In this case, sucrose is the solute and water is the solvent. First, convert your 125g of sucrose to moles...molar mass of sucrose = 342.34 soo you have .365 moles of sucrose. Since you have exactly one L of solution, the molarity of the solution is .365 M
To get a 12 mass% sucrose sol'n dissolve 12.0 g sucrose in 88.0 gram (near 88 ml) of water.
If you think to 2 M and sucrose the needed mass is 51,3 g.