The molecular mass of Sucrose C12H22O11 is 342 a.m.u, so simply dissolve 342g sucrose in water to make the solution 1dm3.
when 342 gsucrose is added in 1 litre water or 34.2 g are added in 100 mls. water 1 molar solution is formed.
A compressor that takes in air at atmospheric and delivers it at a high pressure
100 mL of solution 1 M mixed with 900 mL distilled water
15 grams sugar per liter is the concentration, in terms of mass per volume. To express the concentration in molarity (assuming the sugar is sucrose): 15 g sucrose * (1 mole sucrose / 342 g sucrose) / 1 L = 0.0439 M aqueous sucrose
combine 100 mL 6 M HCl with 500 mL H2O
148g
Dissolve 111 g anhydrous CaCl2 in 1 L distilled water.
1 molar solution of sugar water contains 342,3 g sucrose.
100 mL of solution 1 M mixed with 900 mL distilled water
I am assuming you are refering to a one molar solution. I am also assuming that you have simplified the problem, because sucrose takes up space in water, so a 1 molar solution of sucrose would have less than 1000mL of water. I do not know the what volume of solution is desired, so I will use one liter in my equation. For the sake of organization: 1L sucrose solution * (0.2 moles sucrose/ 1L) * (342.12 g/ 1 mole sucrose) = 68.42 g sucrose In one liter there will be 1000 mL of water (if you simplify the equation so that sucrose doesn't displace any water). In summary: in a 0.2 molar solution of sucrose, there are 68.2 grams of sucrose.
The term molar it refers a form to know the concentration of a solution, and it is equivalent to a molar unit in a litre of solvent 1 Molar (1M) = 1 mole (molecular weight from the structure you are interested in) / 1000 mL or 1 L. Milimolar is the thousandth part from a solution 1M
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
6.023 X 1023 particles make up a 1M solution.
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
15 grams sugar per liter is the concentration, in terms of mass per volume. To express the concentration in molarity (assuming the sugar is sucrose): 15 g sucrose * (1 mole sucrose / 342 g sucrose) / 1 L = 0.0439 M aqueous sucrose
combine 100 mL 6 M HCl with 500 mL H2O
148g
They're actually exactly the same in that neither of them exists.