The molecular mass of Sucrose C12H22O11 is 342 a.m.u, so simply dissolve 342g sucrose in water to make the solution 1dm3.
To calculate the number of moles in 342g of sucrose, divide the given mass by the molar mass of sucrose. The molar mass of sucrose (C12H22O11) is approximately 342.3 g/mol. Therefore, 342g of sucrose is equal to 1 mole.
To make a 0.1 molar solution from a 1.0 molar solution, you would dilute the original solution by a factor of 10. For example, you could mix 1 part of the 1.0 molar solution with 9 parts of solvent (like water) to achieve a final concentration of 0.1 molar.
To calculate the grams of sucrose in 1 liter of soda with a molarity of 0.75 moles, you would first need to know the molar mass of sucrose, which is 342.3 g/mol. Next, you would use the formula: grams = moles x molar mass. Therefore, in this case, the amount of sucrose in 1 liter of soda would be 256.725 grams.
To make a 1 molar solution of glucose in 0.5 L of water, you would need to dissolve 90.1 grams of glucose powder. This is because the molar mass of glucose (C6H12O6) is approximately 180.2 g/mol, and for a 1 molar solution in 0.5 L of water, you would need 1 mole of glucose, which is 180.2 grams.
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
1 molar solution of sugar water contains 342,3 g sucrose.
To calculate the number of moles in 342g of sucrose, divide the given mass by the molar mass of sucrose. The molar mass of sucrose (C12H22O11) is approximately 342.3 g/mol. Therefore, 342g of sucrose is equal to 1 mole.
To make a 0.1 molar solution from a 1.0 molar solution, you would dilute the original solution by a factor of 10. For example, you could mix 1 part of the 1.0 molar solution with 9 parts of solvent (like water) to achieve a final concentration of 0.1 molar.
I am assuming you are refering to a one molar solution. I am also assuming that you have simplified the problem, because sucrose takes up space in water, so a 1 molar solution of sucrose would have less than 1000mL of water. I do not know the what volume of solution is desired, so I will use one liter in my equation. For the sake of organization: 1L sucrose solution * (0.2 moles sucrose/ 1L) * (342.12 g/ 1 mole sucrose) = 68.42 g sucrose In one liter there will be 1000 mL of water (if you simplify the equation so that sucrose doesn't displace any water). In summary: in a 0.2 molar solution of sucrose, there are 68.2 grams of sucrose.
To calculate the grams of sucrose in 1 liter of soda with a molarity of 0.75 moles, you would first need to know the molar mass of sucrose, which is 342.3 g/mol. Next, you would use the formula: grams = moles x molar mass. Therefore, in this case, the amount of sucrose in 1 liter of soda would be 256.725 grams.
A 5% sucrose solution has 5 grams of sucrose in every 100 grams of solution. As 1mL of water has a mass of 1 gram, you should dissolve 5 grams of sucrose in 95 mL of water.
6.023 X 1023 particles make up a 1M solution.
What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.
To make a 1 molar solution of sodium azide, you would need to dissolve 65.01 g of sodium azide in water to make 1 liter of solution. Since you have 98 mg of sodium azide, you would need to add enough water to make a final volume of 1 liter to create the 1 molar solution.
No. For the physical formula ratio, of [solute:solvent] to be the same, you would have to use twice as much glucose as sucrose, to make the solution; because sucrose is a disaccharide. But, when preparing the solution, the actual weight used will be approximately the same. You have a solution, with solute sucrose, at 1C ratio. Weighing the same amount of glucose (in grams), will make a solution of 2C ratio. General expression is Glucose:Sucrose::2:1.
.05 L x 342 (this is the molecular weight of sucrose) x 1.75 = 29.925g
A 1.0 molar solution would be made up by dissolving the the molecular weight of glucose (in grams) in one litre. The molecular weight of glucose is 180.1559g; so a 1.0M solution would be 180.1559g in 1 litre. A 0.5M solution would be half that strong, so that would need 90.0780g in 1 litre. For 500ml you'd need take half the weight into half the volume, so that would be 45.0390g dissolved in water and made up to 500ml.