To make water using NaOH, you can react it with an acid, such as HCl. The reaction is
NaOH + HCl ---> NaCl + H2O. 2.75x10^4 moles of NaOH will produce 2.75x10^4 moles of water because the ratio of NaOH to H2O is 1 to 1 (see equation). Thus, the mass of water formed will be
2.75x10^4 moles H2O x 18 g/mole = 4.95x10^5 grams of water (495 kg)
Yes, benzoic acid is soluble in NaOH because when it reacts with NaOH, it forms the water-soluble salt sodium benzoate.
NaOH is formed then. NaOH is a strong base.
When hydrochloric acid (HCI) reacts with sodium hydroxide (NaOH), a neutralization reaction occurs which forms sodium chloride (NaCl) and water (H2O). The balanced chemical equation is: HCl + NaOH -> NaCl + H2O.
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
Yes, benzoic acid is soluble in NaOH because when it reacts with NaOH, it forms the water-soluble salt sodium benzoate.
It forms NaOH... And its reacts with explosion. .depends on quantity of Na
Sodium violenty reacts with water and evolves H2 gas and forms NaOH... The reaction is 2 Na + 2 H2O -> 2 NaOH + H2 + heat
NaOH is formed then. NaOH is a strong base.
When hydrochloric acid (HCI) reacts with sodium hydroxide (NaOH), a neutralization reaction occurs which forms sodium chloride (NaCl) and water (H2O). The balanced chemical equation is: HCl + NaOH -> NaCl + H2O.
Sodium chloride (NaCl) would be left behind after evaporating the solution to dryness. This is because when sodium hydroxide (NaOH) reacts with hydrochloric acid (HCl), it forms sodium chloride and water. Evaporating the water leaves behind solid sodium chloride.
When sulfuric acid (H2SO4) reacts with sodium hydroxide (NaOH), the salt produced is sodium sulfate (Na2SO4) along with water.
Yes, sodium oxide (Na2O) does dissolve in water. When sodium oxide reacts with water, it forms sodium hydroxide (NaOH), which is a strong base.
The chemical reaction is:Na2Cr2O7 + 2 NaOH = 2 Na2CrO4 + H2O
When sodium hydroxide (NaOH) reacts with carbon dioxide (CO2), it forms sodium carbonate (Na2CO3). This reaction occurs because the NaOH reacts with the CO2 to produce sodium carbonate as a specific compound.
C6H5COOH + NaOH + I2 -----------> C6H5COOI + NaI + H2O
The reaction between hydrochloric acid (HCl) and solid sodium hydroxide (NaOH) forms water (H2O) and sodium chloride (NaCl) as the products. This reaction is a neutralization reaction that produces a salt and water.