Zinc (Zn) does not have variable valency
The valency of Fe in Fe2O3 is +3. This is because oxygen typically has a valency of -2 and there are three oxygen atoms present in Fe2O3, making the overall charge -6. To balance the charge, the iron (Fe) atoms must have a valency of +3.
The balanced chemical equation for the reaction of iron (Fe) with copper (Cu) is: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
molecular equation: CuSO4 (aq)+Fe (s) --> Cu(s) + FeSO4(aq) net ionic equation: Cu2+(aq) + Fe2+ (s) --> Cu2+(s) + Fe2+(aq) spectator ion: Sulfate Ion (SO42-)
There is NO reaction. FeSO4 + Cu --> (nothing) (The opposite reaction works well: Iron wire in copper sulfate) (CuSO4 + Fe --> FeSO4 + Cu)
The valency of ferrocyanide is -4. This is because each cyanide ion (CN-) has a charge of -1, and there are four cyanide ions in the ferrocyanide complex [Fe(CN)6]4-.
Variable valencies are the valencies which can change e.g. Fe (iron) can either have the valency of 2 (Fe II) or 3 (Fe III)
Variable valencies are the valencies which can change e.g. Fe (iron) can either have the valency of 2 (Fe II) or 3 (Fe III)
Certain elements combine with other atoms, donating, accepting or sharing electrons in different proportions depending on the nature of the reaction. For example, iron combines with oxygen to form ferrous oxide as well as ferric oxide. In the formation of ferrous oxide, iron exhibits a valency of +2, whereas in ferric oxide, it has a valency of +3. This is termed variable valency
The valency of Fe in Fe2O3 is +3. This is because oxygen typically has a valency of -2 and there are three oxygen atoms present in Fe2O3, making the overall charge -6. To balance the charge, the iron (Fe) atoms must have a valency of +3.
Fe + Cu(NO3)2 --> Fe(No3)2 + Cu
The balanced chemical equation for the reaction of iron (Fe) with copper (Cu) is: Fe(s) + CuSO4(aq) → FeSO4(aq) + Cu(s)
To determine the overall voltage of the reaction involving iron (Fe) and copper (Cu), you need to look at the standard reduction potentials for both half-reactions. The reduction potential for Fe³⁺/Fe is approximately -0.77 V, while for Cu²⁺/Cu it is +0.34 V. The overall cell potential can be calculated by subtracting the reduction potential of the anode (Fe) from that of the cathode (Cu), resulting in a voltage of approximately +1.11 V for the reaction.
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Copper (Cu) and iron (Fe) in their solid forms (Cu(s) and Fe(s)) are considered elements, as they consist of only one type of atom each. When combined, they do not form a compound unless they undergo a chemical reaction to create a new substance. Therefore, Cu(s) plus Fe(s) remains a mixture of elements rather than a compound.
Hg, Cu, Fe, W
Metals like Al, Fe, Cu
yes.