oh
OH- is a base radical because it can accept a proton (H+) to form water (H2O). Acids, on the other hand, donate protons in a chemical reaction.
OH - ? Strangely enough it is water! H2O.
The ionic product of water refers to the equilibrium constant for the dissociation of water into its ions, H+ and OH-. It is represented by the equation: Kw = [H+][OH-]. At 25°C, the value of Kw is 1.0 x 10^-14.
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
The conjugate acid for the base OH- is H2O. This is because when OH- accepts a hydrogen ion (H+), it forms water (H2O).
OH- is a base radical because it can accept a proton (H+) to form water (H2O). Acids, on the other hand, donate protons in a chemical reaction.
The equation for the dissociation of water is: H2O ↔ H+ + OH-
OH - ? Strangely enough it is water! H2O.
The ionic product of water refers to the equilibrium constant for the dissociation of water into its ions, H+ and OH-. It is represented by the equation: Kw = [H+][OH-]. At 25°C, the value of Kw is 1.0 x 10^-14.
The molecule formed will be water. H+ + OH- = H2O.
i think its 2NaOH + Cl2 ------------> NaClO + NaCl + H2O i think
The conjugate acid for the base OH- is H2O. This is because when OH- accepts a hydrogen ion (H+), it forms water (H2O).
The concentration of OH- decreases as the concentration of H+ increases. This is beacause there is an equilibrium H2O <-> H+ + OH- and therefore the [H+][OH-] is a constant
The net ionic equation for the given reaction would be: H+ + OH- -> H2O
H2O can be spelled out as dihydrogen monoxide (water). It is spoken as "H-two-oh."
The equation is:H+ + (NO3)- + Na+ + (OH)- = (NO3)- + Na+ + H2O (2 H+ OH-)
Water is H2O and the ions are H+ and OH-.