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p1.V1 = p2.V2 (Boile-GayLussac's gas law)

755(torr)*1105(mL) = p2(torr)*1.00(mL)

The pressure is 755*1105= 8.34*105 torr = 1098 atm. (which looks rather high to me for practical purposes, and maybe oxygen / nitrogen become fluidised;

moreover is your cylinder designed for pressure over -safety!- 3000 atm??)

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Q: What pressure is needed to compress the air in a 1.105 liter cylinder at 755 torr to a volume of 1.00 ml?
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