When a sulfate solution reacts with sodium hydroxide solution, a white precipitate of insoluble sodium sulfate is formed. This reaction is a double displacement reaction where the cations and anions of the two compounds switch partners to form the new compound.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
When sodium hydroxide is added to copper sulfate solution, a blue precipitate of copper hydroxide forms. This reaction can be summarized by the equation: CuSO4 (aq) + 2 NaOH (aq) → Cu(OH)2 (s) + Na2SO4 (aq).
When sodium hydroxide solution is added to ammonium hydroxide, a double displacement reaction occurs. Ammonium hydroxide is a weak base and sodium hydroxide is a strong base. The reaction produces water, sodium hydroxide, and ammonia gas.
A brown precipitate of iron(III) hydroxide will form, along with the sodium sulfate remaining in solution. The iron(III) hydroxide precipitate will settle at the bottom of the container.
When excess hydroxide solution is added to copper II sulphate solution, a precipitate of copper II hydroxide forms. The balanced chemical equation for this reaction is CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4. In this reaction, the blue color of the copper II sulfate solution turns into a light blue precipitate of copper II hydroxide.
When copper sulfate is added to sodium hydroxide, a blue precipitate of copper hydroxide is formed. The color change observed is from the initial blue color of copper sulfate to the blue precipitate of copper hydroxide.
When sodium hydroxide is added to copper sulfate solution, a blue precipitate of copper hydroxide forms. This reaction can be summarized by the equation: CuSO4 (aq) + 2 NaOH (aq) → Cu(OH)2 (s) + Na2SO4 (aq).
A white precipitate of barium sulphate is formed when sodium sulphate solution is added to barium chloride solution. This is due to the formation of an insoluble salt, barium sulphate, which appears as a white solid in the solution.
sodium hydroxide solution
When sodium hydroxide solution is added to ammonium hydroxide, a double displacement reaction occurs. Ammonium hydroxide is a weak base and sodium hydroxide is a strong base. The reaction produces water, sodium hydroxide, and ammonia gas.
You would need to add Sulphuric acid to make Sodium Sulphate + Water :)
A brown precipitate of iron(III) hydroxide will form, along with the sodium sulfate remaining in solution. The iron(III) hydroxide precipitate will settle at the bottom of the container.
No. Sodium hydroxide releases hydroxide ions, which actually take protons out of the solution. This qualifies sodium hydroxide as a base.
Sodium sulfate solution is neutral; the red litmus is purple.
dark green (but orange - brown if left standing)
When excess hydroxide solution is added to copper II sulphate solution, a precipitate of copper II hydroxide forms. The balanced chemical equation for this reaction is CuSO4 + 2NaOH -> Cu(OH)2 + Na2SO4. In this reaction, the blue color of the copper II sulfate solution turns into a light blue precipitate of copper II hydroxide.
Sodium sulphate increases the concentration of sulphate ions. So strontium sulphate solubility decreases.