In this case a cation-vacancy defect is created.
The mole ratio of BaCl2 to AgCl is 1:2. This means that for every 1 mole of BaCl2, 2 moles of AgCl are produced in the chemical reaction.
AgNo3(aq) + NaCl(aq) -------------->AgCl (ppt) + No3(-) + Na(+) no silver nitrates are produced it is all consumed. only silver chloride is produced and precipitate . free nitrate and free sodium ions are produced but do not react with each other 1 Mole AgNo3 ------->169.9 gm 1 Mole Nacl ------->58.4 gm 1 Mole AgCl ------->143.3 gm 4.02 gm AgNO3 = (4.02 / 169.9) = 0.02366 M AgCl produced = 0.02366 M = 3.39 gm
trick question guys, there is none. this question should be deleted for such stupidity. FOOCK CHEMISTRY!
3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.
AgCl has a higher lattice energy than AgBr because Cl- is a smaller ion than Br-, resulting in stronger electrostatic interactions in AgCl.
The electrical conductivity is modified.
In the frenkel defect the ions are not removed from the crystal.so there will be no change in the crystal structure. that is there is no decrease in the no of ions.all the ions are inside the crystal.they are only dislocated.
The balanced chemical equation for this reaction is: AgNO3 + NaCl -> AgCl + NaNO3 From this equation, we can see that 1 mole of AgNO3 produces 1 mole of AgCl. Since the molar mass of AgNO3 is 169.87 g/mol, 83.0 g of AgNO3 is equivalent to 0.488 moles. Therefore, 0.488 moles of AgCl will be produced.
The mole ratio of BaCl2 to AgCl is 1:2. This means that for every 1 mole of BaCl2, 2 moles of AgCl are produced in the chemical reaction.
AgNo3(aq) + NaCl(aq) -------------->AgCl (ppt) + No3(-) + Na(+) no silver nitrates are produced it is all consumed. only silver chloride is produced and precipitate . free nitrate and free sodium ions are produced but do not react with each other 1 Mole AgNo3 ------->169.9 gm 1 Mole Nacl ------->58.4 gm 1 Mole AgCl ------->143.3 gm 4.02 gm AgNO3 = (4.02 / 169.9) = 0.02366 M AgCl produced = 0.02366 M = 3.39 gm
To determine the mass of silver chloride produced, we need to know the balanced chemical equation for the reaction between silver nitrate (AgNO3) and sodium chloride (NaCl) that produces silver chloride (AgCl) as a precipitate. Once we have the balanced equation, we can use the stoichiometry of the reaction to determine the number of moles of AgCl produced, and then convert that to mass using the molar mass of AgCl.
AgCl is highly insoluble, as it is a precipitate.
trick question guys, there is none. this question should be deleted for such stupidity. FOOCK CHEMISTRY!
3.56 g 3 AgNO3 + AlCl3 --> 3 AgCl + Al(NO3)3 AgCl3 is the limiting reagent (I checked), so: 4.22 g AgNO3 * (1 mol AgNO3/169.88 g AgNO3) * (3 mol AgNO3/3 mol AgCl3) * (143.32 mol AgCl3/1 mol AgCl3) =3.56 g AgCl3See the Related Questions to the left for more information about solving stoichiometry problems of this nature.
The chemical compound name for AgCl is silver chloride.
AgCl has a higher lattice energy than AgBr because Cl- is a smaller ion than Br-, resulting in stronger electrostatic interactions in AgCl.
No, AgCl is not organic. It is an inorganic compound composed of silver and chlorine.