CS2 is the chemical formula of carbon disulfide.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
C(s) + 2S(s) + 89.4 kJ --> CS2(l)
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
the chemical formula for carbon disulfide is CS2.
No. CS2 is not an electrolyte because CS2 can't be ionised as independent carbon ion does not exist.
It is not a reaction, it is a compound: CS2, toxic flammable stinky fluid (rotten cauliflower)
The enthalpy of formation of carbon disulfide (CS2) can be indicated by the reaction: C(s) + 2 S(s) → CS2(l). This reaction represents the formation of one mole of CS2 from its elements in their standard states. The enthalpy change associated with this reaction is +89.4 kJ/mol, meaning that 89.4 kJ of energy is absorbed when one mole of CS2 is formed from solid carbon and solid sulfur.
If 3 moles of SO2 reacts, then 3 moles of CS2 will form since the reaction ratio between SO2 and CS2 in the reaction is 1:1.
C(s) + 2S(s) + 89.4kJ --} CS2(l)
C(s) + 2S(s) + 89.4 kJ --> CS2(l)
imidazole will form
ionic
The balanced equation is 2 CS2 + 3 O2 → 2 CO2 + 2 SO2. This equation balances the number of atoms for each element on both sides of the reaction.
When CS2 is added to reaction mixture Fe + S = FeS , it would dissolve the excess 'S' leaving the solids Fe and FeS without any change.
the chemical formula for carbon disulfide is CS2.
The balanced chemical equation for the reaction is: C + 2SO2 → CS2 + 2O2. From the equation, 1 mole of carbon produces 1 mole of CS2. Therefore, if 5.9 moles of carbon react, 5.9 moles of CS2 are produced.
The chemical equation for the combustion of carbon disulfide (CS2) is: CS2 + 3O2 -> CO2 + 2SO2. From the balanced equation, 2 moles of CS2 will produce 2 moles of SO2. The volume of SO2 gas formed will depend on the temperature, pressure, and volume of the reaction, as well as the ideal gas law equation (PV = nRT).