KCl shows Frenkel defect, where a cation is displaced from its lattice site into interstitial spaces. This occurs due to the large size difference between K+ and Cl- ions, making it easier for the smaller K+ ion to move into interstitial spaces without disturbing the overall charge balance of the crystal.
2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
1. Identify (a) through (d) as reactants or products. Type your answers in the spaces provided: (a) (b) (c) (d) KOH + HCl KCl + H2O
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
This would be considered a saturated solution if all 25g of KCl are completely dissolved in the 100g of water at 30 degrees Celsius.
KCl is highly soluble in water and some other solvents.
ionic crystal
The coefficient of potassium chloride (KCl) typically refers to its solubility product constant (Ksp) in aqueous solutions or its stoichiometric coefficients in chemical equations. In terms of stoichiometry, KCl has a coefficient of 1 when it is represented in a balanced equation. If you're asking about its solubility, KCl is highly soluble in water, with a solubility of about 34.2 g per 100 mL at room temperature. If you meant something else by "coefficient," please clarify!
2 KClO3 -> KCL + 3O2 Molar weight of O2 = 32 grams/mole (so close it doesn't matter) 30 grams/32grams/mole = 0.9375 moles Molar weight of KCL = 39+35.5 = 74.5 grams/mole (Want more accuracy? Do it yourself?) now if we have 3 moles of O2 then we have 2 moles of KCl. If we have one mole of O2 then we have 2/3 moles of KCL What ever moles we have of O2 we must multiply it by 2/3 to get the moles of KCl So we have 0.9375moles of O2 x 2/3 = 0.625 moles of KCl So 0.625 moles of KCl x 74.5 grams/mole KCl = 46.5625 grams KCl
1. Identify (a) through (d) as reactants or products. Type your answers in the spaces provided: (a) (b) (c) (d) KOH + HCl KCl + H2O
moles KCl = ( M solution ) ( V solution in L )moles KCl = ( 2.2 mol KCl / L solution ) ( 0.635 L of solution )moles KCl = 1.397 moles KCl
Potassium chloride (KCl) has an ionic bond.
moles KCL = ( M solution ) ( L of solution )moles KCl = ( 0.83 mol KCl / L ) ( 1.7 L ) = 1.41 moles KCl
To balance the chemical equation KCl, you need to make sure there are equal numbers of each type of atom on both sides of the equation. You achieve balance by adjusting the coefficients in front of the compounds in the equation. In the case of KCl, you would put a coefficient of 1 in front of KCl on both sides of the equation to balance it.
The equation that describes this process is as follows: 2KClO3 ---> 2KCl + 3O2 For every 2 moles of reactants consumed 3 moles of oxygen gas are produced. 3 mol O2 / 2 mol KClO3 = x mol O2 / 12.3 mol KClO3 x = 12.3 mol x 3 mol / 2 mol = 18.45 mol Therefore, 18.5 mol (3 significant figures) of oxygen are produced by the decomposition of 12.3 mol of potassium chlorate
KCl is soluble in DMF
KCl is a compound not an element.
KCl is 'potassium chloride'.