16ml of 0.1M sodium hydroxide solution needs 20ml of 0.08M sulfuric acid to reach end point.
M = n ÷ V M-Molarity (mol/l) n- moles V- volume in liters. Volume cannot be expressed in grams....
In order to prepare exactly 30 mL of 1M NaOH solution, a volumetric vessel that contains exactly 30 mL when full to a marked level will be needed. By definition, a 1 M solution contains one mole in a liter of volume, and since solutions are homogeneous, 30 mL of such a solution will require (30/1000) mole of sodium hydroxide. The molar mass of NaOH is about 40, corresponding to 1.2 grams of sodium hydroxide, which can be determined by weighing solid sodium hydroxide, dissolving the weighed amount in a volume of water less than the 30 mL capacity of the volumetric vessel, transferring this more concentrated solution into the volumetric vessel, and diluting with pure water until the 30 mL volume is contained in the vessel.
This sodium hydroxide solution has a molarity of 0,25.
Make sure that the equation is balanced. NaOH + HNO3 > > NaNO3 + H2O ( all one to one ) 15.0 grams NaOH (1mol NaOH=39.998g) (1mol HNO3/1mol NaOH) = 0.375 moles of HNO3 Molarity = mols solute/volume solution 2.00M HNO3 = 0.375 mols/X volume = 0.188 Liters or, 188 milliliters.
eat people In water NaOH becomes a strong base and can dissolve things like human skin and is used as a drain cleaner. When small amounts of water are added to dry NaOH, the reaction generates heat.
use titration formula
First, you must either find or be provided with a known mass of sodium hydroxide and a volumetric vessel. You must also know the molecular mass of sodium hydroxide, which is about 40.00. If the volume of sodium is sufficient, you can complete the preparation by determining the volume of the volume of the vessel in litres, multiply this volume by twice the molecular mass of sodium hydroxide, and dissolve the resulting mass in the known volume.
2.0 M
Check the spelling: 150 M ?
10 ml of 0.0500 M Phosphoric acid
A solution of sulfuric acid will have the same properties as any other liquid. It will have a definite volume but its shape will be that of its container.
M = n ÷ V M-Molarity (mol/l) n- moles V- volume in liters. Volume cannot be expressed in grams....
1) Add 2cm3 of solution to be tested to a test-tube. 2) Add an equal volume of 5% potassium hydroxide* solution and mix. 3) Add 2 drops of 1% copper sulphate solution and mix. A mauve or purple colour develops if protein is present. *Sodium hydroxide solution can be used instead of potassium hydroxide solution.
Quantitative observations involve numbers. An example would be the volume of 0.1M HCl needed to neutralise 25 ml of sodium hydroxide solution.
347 mL
When sodium hydroxide absorb carbon dioxide sodium carbonate is formed. But we need a defined mass (volume) of NaOH for a titration.
In order to prepare exactly 30 mL of 1M NaOH solution, a volumetric vessel that contains exactly 30 mL when full to a marked level will be needed. By definition, a 1 M solution contains one mole in a liter of volume, and since solutions are homogeneous, 30 mL of such a solution will require (30/1000) mole of sodium hydroxide. The molar mass of NaOH is about 40, corresponding to 1.2 grams of sodium hydroxide, which can be determined by weighing solid sodium hydroxide, dissolving the weighed amount in a volume of water less than the 30 mL capacity of the volumetric vessel, transferring this more concentrated solution into the volumetric vessel, and diluting with pure water until the 30 mL volume is contained in the vessel.