This volume is 65,68 L.
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g
To determine the number of atoms in 132 grams of xenon, you first need to calculate the number of moles using the molar mass of xenon (131.3 g/mol). Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. This will give you the number of xenon atoms in 132 grams.
A Hershey bar weighs 43g, so 3 weigh 129g.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
Barium-132 decays through beta-minus decay, where a neutron in the nucleus is converted into a proton, releasing an electron and an antineutrino in the process. The resulting element after decay is cesium-132.
there are 132, 000 grams in 132 kg
132 g = 0.132 kg
1/10) of 132 ounces = 374.213705 grams
28.35 grams = 1 ounce, so 132 grams = 132/28.35 ounces = 4.66 ounces
That is approximately 132 grams per cup
132 ounces = 3742 grams (approximately).
0.132 kg
100 grams = 132 calories
1/5
Cobra beer has 132 calories in it. It also has 0 grams of fat and 10 grams of carbohydrates.
The first chapter in Fruits Basket volume 23 is 132.
First you need to write a balanced equation. You are given that propane undergoes a combustion reaction that produces carbon dioxide and water.Unbalanced: C3H8 + O2 ---> CO2 + H2OBalanced: C3H8 + 5O2 ---> 3CO2 + 4H2OGivens:42.0 grams C3H8 (Molecular mass 44.0 g)115.0 grams O2 (Molecular mass 32.0 g)Molecular mass of CO2: 44.0 gMole ratio 1:5:3:4 (C3H8:O2:CO2:H2O)Then you need to find which of the reactants are the limiting reactant (lowest value) and which is the excess reactant. The limiting reactant is what you will base the rest of the problem on. To do this, you convert each measurement to moles from grams.42.0 g C3H8 / (44.0 g) = .955 moles C3H8 115.0 g