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CrCl3 needs to be in a solution with water first. The addition of sodium carbonate will react with the solution forming hydroxide ions, which willreact with the Cr3+ ions in the solution to form a green precipitate, Cr(OH)3.

CO3- = CO2 + O2-

O2- + H2O = 2 OH-

Cr3+ (aq) + 3OH- (aq) = Cr(OH)3

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What is the reaction for Na2CO3 plus HCl?

The reaction between Na2CO3 (sodium carbonate) and HCl (hydrochloric acid) produces NaCl (sodium chloride), H2O (water), and CO2 (carbon dioxide). The balanced chemical equation for this reaction is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2.


What is the balanced equation for the chemical reaction of sodium carbonate and hydrochloric acid?

The balanced chemical equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) is: Na2CO3 + 2HCl → 2NaCl + H2O + CO2


What will HCl plus Na2CO3 produce?

Youwill getCO2 (g) + H2O (l) + NaCL(aq)don't forget to balance the equation!!!


What type of reaction between HCl and na2co3?

The reaction between HCl and Na2CO3 is a double displacement reaction, also known as a neutralization reaction. The products formed are sodium chloride (NaCl), carbon dioxide (CO2), and water (H2O). This reaction occurs when an acid (HCl) reacts with a base (Na2CO3) to form a salt (NaCl) and water.


What happens when hydrochloric acid is added to sodium bicarbonate?

When HCl reacts with Na2CO3, an acid-base neutralization reaction takes place. 2HCl + Na2CO3 = 2NaCl + H2CO3 H2CO3 further decomposes to give H2O and CO2.


What is the mole ratio of sodium carbonate reacting with HCL?

The balanced chemical equation for the reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) is: Na2CO3 + 2HCl -> 2NaCl + H2O + CO2 Therefore, the mole ratio of sodium carbonate to HCl is 1:2. This means that for every 1 mole of sodium carbonate, 2 moles of HCl are needed for the reaction.


What volume of 0.100 M HCl is required to completely react with ml of 0.161 M Na2CO3?

To solve this problem, we need to use the balanced chemical equation between HCl and Na2CO3. From the equation, we can see that it is a 1:2 ratio for HCl to Na2CO3. Therefore, we need twice the volume of 0.161 M Na2CO3 to react completely with HCl. Calculate the volume of HCl required by multiplying the volume of Na2CO3 by 2.


Equation between na2co3 and hcl?

The chemical equation is:Na2CO3 + 2 HCl = 2 NaCl + CO2 + H2O


How many grams of HCL needed to react with 4000 g of Na2co3?

The balanced chemical equation for this reaction is 2 HCl + Na2CO3 -> 2 NaCl + H2O + CO2. From the equation, 1 mole of Na2CO3 reacts with 2 moles of HCl. Calculate the number of moles of Na2CO3 in 4000g, then use the mole ratio to find the moles of HCl needed. Finally, convert moles of HCl to grams.


What is the molecular formula for sodium carbonate plus hydrochloric acid?

The reaction between sodium carbonate (Na2CO3) and hydrochloric acid (HCl) produces sodium chloride (NaCl), carbon dioxide (CO2), and water (H2O). The balanced chemical equation is: Na2CO3 + 2HCl → 2NaCl + CO2 + H2O.


How do you write the balance chemical equation for the reaction between hydrochloric acid and sodium carbonate?

The balanced chemical equation for the reaction between hydrochloric acid (HCl) and sodium carbonate (Na2CO3) is: 2HCl + Na2CO3 → 2NaCl + H2O + CO2. This balanced equation shows that two moles of hydrochloric acid react with one mole of sodium carbonate to produce two moles of sodium chloride, one mole of water, and one mole of carbon dioxide.


What are the products of hydrochloric acid plus sodium carbonate?

The products of hydrochloric acid (HCl) and sodium carbonate (Na2CO3) are sodium chloride (NaCl), water (H2O), and carbon dioxide (CO2). The balanced chemical equation for this reaction is: 2HCl + Na2CO3 -> 2NaCl + H2O + CO2.