One to one (or two to two, which is the same as one to one).
In the thermal decomposition of sodium bicarbonate (bicarbonate of soda, NaHCO3) to form sodium carbonate (soda ash, Na2CO3) and carbon dioxide (CO2), the stoichiometric relationship is 2 moles of NaHCO3 producing 1 mole of Na2CO3 and 1 mole of CO2. This means that for every mole of sodium bicarbonate decomposed, you'll get one mole of sodium carbonate and one mole of carbon dioxide.
The molar mass of sodium carbonate is approximately 106 grams per mole.
Since sodium carbonate dissociates into two sodium ions for every one formula unit, one mole of Na2CO3 will provide 2 equivalents of sodium ions. Therefore, a 0.0100 M solution of sodium carbonate will contain 0.0200 equivalents of sodium ions per liter of the solution.
Since the volume ratio of two gases in a chemical reaction is directly proportional to the mole ratio of the reactants, you can infer that the mole ratio of lead nitrate to sodium iodide in their reaction is the same as the volume ratio of the gases involved. This allows you to determine the stoichiometry of the reaction.
3 x 2 x 23 = 138g
In the thermal decomposition of sodium bicarbonate (bicarbonate of soda, NaHCO3) to form sodium carbonate (soda ash, Na2CO3) and carbon dioxide (CO2), the stoichiometric relationship is 2 moles of NaHCO3 producing 1 mole of Na2CO3 and 1 mole of CO2. This means that for every mole of sodium bicarbonate decomposed, you'll get one mole of sodium carbonate and one mole of carbon dioxide.
0.2 mole of sodium carbonate, Na2CO3, contains approximately 11.16 grams of sodium carbonate.
The molar mass of sodium hydrogen carbonate (NaHCO3) is approximately 84 grams per mole. Therefore, the mass of 1.00 mole of sodium hydrogen carbonate would be 84 grams.
The molar mass of sodium carbonate is approximately 106 grams per mole.
The formula is: NaOH(aq) + HCl(aq) --> NaCl + H2O(l) So the ratio is: 1 : 1 : 1 : 1
A 1M solution of sodium carbonate means that it contains 1 mole of sodium carbonate dissolved in 1 liter of solvent (usually water). This concentration is used in chemistry to describe the amount of the solute (sodium carbonate) present in the solution.
Since sodium carbonate dissociates into two sodium ions for every one formula unit, one mole of Na2CO3 will provide 2 equivalents of sodium ions. Therefore, a 0.0100 M solution of sodium carbonate will contain 0.0200 equivalents of sodium ions per liter of the solution.
Since the volume ratio of two gases in a chemical reaction is directly proportional to the mole ratio of the reactants, you can infer that the mole ratio of lead nitrate to sodium iodide in their reaction is the same as the volume ratio of the gases involved. This allows you to determine the stoichiometry of the reaction.
It depends on what it is reacting with.
3 x 2 x 23 = 138g
one mole sodium carbonate contains 23X2 sodium, for three moles it will be 23X2X3=138 gram;
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------