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A 1M solution of sodium carbonate contains 1 gram formula mass of sodium carbonate dissolved in each liter of solution.
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How much sodium chloride is required to make 1litre of 1M solution?
0.056g
What is the conductivity of 1M NaOH?
What is the conductivity of 1 molar solution of sodium hydroxide at ambient temperature
How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
How do you prepare 1M sodium phosphate dibasic?
sodium phosphate dibasic means that there are two sodium molecules in the formula (contributing to two bases). the formula is Na2HPO4. the first step is to figure out the molecular weight of the compount with the help of a periodic table. This comes out to 142g/mole. To make 1M solution (M= moles/liter so I am assuming 1 liter) you need 142 grams of the compound in 1L of dH2o. The definition of molarity (which is moles over liters) makes the calculation easy for making 1L of the solution. However if you want to make less or more of the solution, you will have to calculate accordingly. For example if you wanted to make 50 ml (0.05L) of the solution, you would multiply 142 g/liter (g/mol x moles/liter will give g/liter) X 0.05 liter, which would give you 7.1 g. 7.1 g of Na2HPO4 is needed to make 50 ml of 1 M solution. 142 g is needed to make 1000ml (1 L) of 1M solution.
Compare the boiling and freezing points of 1m solution of glucose to a 1m solution of Cacl2. Why does CaCl2 have a higher boiling and a lower freezing Please explain not just say its 1m and then 3m?
Boiling and freezing points are colligative properties, meaning they depend on the number of solute particles dissolve in solution. Glucose is a molecular compound so it is one particle dissolved in solution. CaCl2 will dissociate into three particles in solution. There are three times as many particles present in solution when CaCl2 dissolves.
How much sodium chloride is required to make 1litre of 1M solution?
0.056g
Which phase will be on top in an immiscible mixture of methylene chloride and 1M of sodium hydroxide?
Sodium hydroxide solution will be on the top.
How can we prepare 1M solution of NaCl?
You could titrate equal volumes of 1M solution of NaOH and 1M solution of HCl to obtain 1M solution of NaCl.
What is produced at the cathode of an electrolytic cell containing 1M solution of sodium chloride?
Chlorine gas. Cl2
Calculate the sodium ion concentration when 40.0 mL of 2.5 M sodium carbonate is added to 30.0 mL of 1.0 M sodium bicarbonate?
first of all, let's find the molecular formula for the two substances: Na2(CO3) and Na(HCO3). sodium carbonate has two Na atoms in each molecule and sodium bicarbonate has only one. now let's find the number of moles of sodium carbonate and sodium bicarbonate we have: 2.5M * .04L = .1mol 1M * .03L = .03mol we now know that there are .2mol (.1*2) of Na in sodium carbonate because there's two sodium ions in each sodium carbonate. And we know that there's 1 Na ion in each sodium bicarbonate, so we know it's just .03 mol Na in sodium bicarbonate. add those up: .2mol+.03mol = .23mol Na since Molar = mol/volume, we can find the volume of the whole solution: 30mL + 40mL=70mL or .07L .23mol/.07L is 3.29M
What does it mean that Wash organic layer with 1.0 ml of 1M aqueous sodium bicarbonate?
1m is the molarty of the solution meaning the concentration is 1 mol of baking soda (sodium bicarbonate) to every liter of water. 1 mol of sodium bicarbonate is 84g. so for 1ml of water with a molarity of 1 divide 84g by 1000 which is 84mg and add that to 1ml of water. as far as wahing the organic layer i think it means washing any water from the solution but i may be wrong idk.
What is the conductivity of 1M NaOH?
What is the conductivity of 1 molar solution of sodium hydroxide at ambient temperature
What does 1M glucose solution mean?
1M glucose means that 1 mole of glucose is dissolved in 1kg of water. Since 1M means 1 molal. And molality is equla to no.of moles of solute per kg of water.
A solution of NaOH contains 20g of this compound in 2dm3 of this solution . What is molarity of this solution?
This sodium hydroxide solution has a molarity of 0,25.
How many molecules of NaCl are in the 1 M NaCl solution?
It depends on how much solution you have!"1 molar solution" means that 1 litre of the solution contains 1 mole of solute (in this case, Na+ and Cl- ions). Therefore, 1 litre of 1M NaCl will contain 1 mole of sodium chloride. 1 mole is avagadro's number (6.02x1023) of a substance. If you have two litres of solution, obviously, you will have twice this number, for example.Note, though, that there are NO molecules of sodium chloride - sodium chloride is not a molecular substance.
How many moles of sodium ions and chloride ions are present in 1 liter of a 1M solution of sodium chloride?
Molarity is moles/liter, so in order to find the moles of a substance in a given volume, simply multiply molarity with volume (in liters). n=M*V
How do you prepare 1M sodium phosphate dibasic?
sodium phosphate dibasic means that there are two sodium molecules in the formula (contributing to two bases). the formula is Na2HPO4. the first step is to figure out the molecular weight of the compount with the help of a periodic table. This comes out to 142g/mole. To make 1M solution (M= moles/liter so I am assuming 1 liter) you need 142 grams of the compound in 1L of dH2o. The definition of molarity (which is moles over liters) makes the calculation easy for making 1L of the solution. However if you want to make less or more of the solution, you will have to calculate accordingly. For example if you wanted to make 50 ml (0.05L) of the solution, you would multiply 142 g/liter (g/mol x moles/liter will give g/liter) X 0.05 liter, which would give you 7.1 g. 7.1 g of Na2HPO4 is needed to make 50 ml of 1 M solution. 142 g is needed to make 1000ml (1 L) of 1M solution.
