The reaction is:
Pb(NO3)2 + 2 NaOH = Pb(OH)2 + 2 NaNO3
Lead hydroxide is insoluble in water.
The net ionic equation for the reaction between Pb(NO3)2 and NaOH is: Pb2+ + 2OH- → Pb(OH)2(s). This equation represents the formation of a precipitate of lead(II) hydroxide.
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
The balanced reaction between lead nitrate (Pb(NO3)2) and ammonia (NH3) is: Pb(NO3)2 + 2NH3 → Pb(OH)2 + 2NH4NO3
For lead (II) nitrate: H2SO4 + Pb(NO3)2 -----> 2HNO3 + PbSO4 ...................................................(white)
CaSO4 + Pb(NO3)2 = Ca(NO3)2 + PbSO4But since Pb is less reactive than Ca according to the reactivity series, Pb can not replace the Ca in CaSO4. Therefore, the reaction will not occur.
The net ionic equation for the reaction between Pb(NO3)2 and NaOH is: Pb2+ + 2OH- → Pb(OH)2(s). This equation represents the formation of a precipitate of lead(II) hydroxide.
It has to be Pb(NO3)2 with NaCl as Pb has a +II oxidation state and NO3 has -I oxidation state. The reaction is the following: Pb(NO3)2 +2NaCl ----> PbCl2 + 2NaNO3
Equation is Zn + Pb(NO3)2 --> Zn(NO3)2 + Pb
Pb + 2NO3 - --> Pb(NO3)2
The balanced reaction between lead nitrate (Pb(NO3)2) and ammonia (NH3) is: Pb(NO3)2 + 2NH3 → Pb(OH)2 + 2NH4NO3
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The balanced chemical equation for the reaction of lead foil with silver nitrate solution is: 2AgNO3 + Pb --> Pb(NO3)2 + 2Ag This reaction forms lead(II) nitrate and silver.
For lead (II) nitrate: H2SO4 + Pb(NO3)2 -----> 2HNO3 + PbSO4 ...................................................(white)
2 KNO3 has 6 oxygen atoms.
CaSO4 + Pb(NO3)2 = Ca(NO3)2 + PbSO4But since Pb is less reactive than Ca according to the reactivity series, Pb can not replace the Ca in CaSO4. Therefore, the reaction will not occur.
The balanced chemical equation for the reaction between lead (II) nitrate (Pb(NO3)2) and potassium iodide (KI) is: Pb(NO3)2 + 2KI -> PbI2 + 2KNO3 This equation is already balanced as it has the same number of atoms of each element on both sides of the reaction arrow.
The net ionic equation for the reaction between MgSO4 and Pb(NO3)2 would be Mg2+ + Pb2+ -> MgSO4 + Pb(NO3)2 -> Mg(NO3)2 + PbSO4. The spectator ions are NO3- on both sides of the equation.