One must always first have the correct, balanced, chemical equation in order to answer general chemistry questions like this one. Once the student can answer a question such as this one, he can answer any questions since they all require the same information. The only difference in the questions is that for one question the student may need to convert grams to moles first, and for other questions the student may need to convert moles to grams first. Since the number of moles of any element or compound is directly proportional to the number of atoms or molecules, virtually any question that involves a chemical equation will ultimately require the number of moles, not grams, of each reactant and/or product.
Now, let's solve this very simple question:
The chemical equation must be CuCO3 ---> CO2 + CuO, and it tells us that for each mole of CuO formed, one mole of CuCO3 is consumed, therefore if we know the no. of moles of CuCO3 that reacted, then the same number of moles of CuO was formed. (I am assuming that the reaction goes to completion, that is all of the cupric carbonate reacts.) Thus, all that is needed to answer the question is to: 1) determine the number of moles of CuCO3 that reacted, and 2) calculate the number of grams of CuO that number of moles of CuCO3 would generate according to the chemical equation.
The formula wt. of CuCO3 is: 63.546 + 12.011 + (3)(15.999) = 123.55 g/mol. Thus, 12.35 g of CuCO3 = 12.35 g CuCO3/123.55 g CuCO3/mol CuCO3 = 0.1000 mol CuCO3.
Again, per the chemical equation, one CuO species is generated for each CuCO3 that disproportionates, therefore 0.1000 mol of CuO is created from 0.1000 mol of CuCO3. The molecular wt. of CuO is 63.546 + 15.999 = 79.545 g/mol, hence 0.1000 mol of CuO has a mass of 79.545 g/mol x 0.1000 mol = 7.954 g CuO.
The formula mass of CuCO3 (copper(II) carbonate) is calculated by adding the atomic masses of each element in the compound. For CuCO3, the atomic mass of Cu (copper) is 63.55 g/mol, C (carbon) is 12.01 g/mol, and O (oxygen) is 16.00 g/mol. Therefore, the formula mass of CuCO3 is 63.55 + 12.01 + (3 x 16.00) = 123.56 g/mol.
The mass ratio of elements in copper carbonate can be determined by dividing the mass of each element present by the total mass of the compound. In copper carbonate (CuCO3), the elements are copper (Cu), carbon (C), and oxygen (O). The mass ratio of Cu:C:O in copper carbonate isolated from a mineral would be approximately 1:1:3.
The easiest way to solve these problems is to use what is called a unit multiplier. First begin with the number of grams of copper that you have, then use the unit multiplier that expresses the number of grams per mole of copper (this is the number that corresponds to the atomic mass on the periodic table times grams, divided by moles). Then use the number of copper atoms that it takes to create copper oxide; this will depend on the oxidation state of the copper. Finally it reverse the process by adding up the atomic masses of copper oxide, and that will be the number of grams per mole of copper oxide, returning you from Moles back to Grams.
The value of x can be determined by comparing the masses of CuSO4.xH2O and CuSO4 before and after heating. By calculating the difference in mass, the value of x can be obtained based on the loss of water molecules during the heating process.
When magnesium is heated in air, it reacts with oxygen to form magnesium oxide. The total mass of the system, which includes the magnesium and the oxygen it reacts with, remains the same according to the Law of Conservation of Mass.
1235g because 720 + 5 and a half = 720.5 = 1.235kg = 1235g
12.5 (g CuCO3) = [12.5 (g CuCO3) / 123.555 (g/mol CuCO3)] = 0.1012 (mol CuCO3)0.1012 (mol CuCO3)* [1 (mol CuO) / (mol CuCO3)] = 0.1012 (mol CuO)= [0.1012 (mol CuO) * 79.545 (g/mol CuO)] = 8.047 g CuO = 8.05 g CuO
The formula mass of CuCO3 (copper(II) carbonate) can be calculated by adding the atomic masses of each element in the compound. The atomic masses of copper (Cu), carbon (C), and oxygen (O) are approximately 63.5, 12.0, and 16.0 grams per mole, respectively. Therefore, the formula mass of CuCO3 is around 123.5 grams per mole.
The formula mass of CuCO3 (copper(II) carbonate) is calculated by adding the atomic masses of each element in the compound. For CuCO3, the atomic mass of Cu (copper) is 63.55 g/mol, C (carbon) is 12.01 g/mol, and O (oxygen) is 16.00 g/mol. Therefore, the formula mass of CuCO3 is 63.55 + 12.01 + (3 x 16.00) = 123.56 g/mol.
The mass ratio of elements in copper carbonate can be determined by dividing the mass of each element present by the total mass of the compound. In copper carbonate (CuCO3), the elements are copper (Cu), carbon (C), and oxygen (O). The mass ratio of Cu:C:O in copper carbonate isolated from a mineral would be approximately 1:1:3.
The easiest way to solve these problems is to use what is called a unit multiplier. First begin with the number of grams of copper that you have, then use the unit multiplier that expresses the number of grams per mole of copper (this is the number that corresponds to the atomic mass on the periodic table times grams, divided by moles). Then use the number of copper atoms that it takes to create copper oxide; this will depend on the oxidation state of the copper. Finally it reverse the process by adding up the atomic masses of copper oxide, and that will be the number of grams per mole of copper oxide, returning you from Moles back to Grams.
The value of x can be determined by comparing the masses of CuSO4.xH2O and CuSO4 before and after heating. By calculating the difference in mass, the value of x can be obtained based on the loss of water molecules during the heating process.
The mass number of an atom is obtained by totaling the number of protons and neutrons.
no
No, an empty container will not increase in mass when heated. Heating an empty container will not create additional matter within the container to increase its mass.
no
The symbol for mass of the substance being heated is typically represented by the letter "m" in physics and chemistry equations.