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When 30 grams of water is converted into steam how much heat is absorbed?
Wiki User
∙ 12y ago
q = mHv
q = heat
m = mass (30g)
Hv = heat of vaporization (2,260J/g)
q = (30g)(2,260J/g)
q = 67,800J
When 30 grams of water is converted into steam, how much heat is absorbed?
67,800J of heat, also represented as 67.8kJ of heat is absorbed.
Wiki User
∙ 12y ago
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