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What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
What is the concentration of a HBr if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
What is the concentration of a HBr solution in 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
Balanced equation. KOH + HBr -> KBr + H2O everything is one to one, so... Molarity = moles of solute/liters of solution ( change ml to liters ) 0.25 M KOH = moles KOH/0.015 liters = 0.00375 moles of KOH this is as many moles that you have of HBr, so... Molarity of HBr = 0.00375 moles/0.012 liters = a concentration of HBr that is 0.31 M
KBr a strong or weak base?
KBr is not a base, but a salt formed by the combination of the strong base KOH and the strong acid HBr. It is considered a neutral salt since it does not significantly contribute to the pH of a solution.
What are the numbers for equation koh hbr equals kbr h2o?
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.
What is the concentration of a HBr if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
To find the concentration of HBr, you first need to determine the number of moles of KOH that react with the HBr. This can be done using the volume and concentration of KOH solution. Then, using the stoichiometry of the neutralization reaction between HBr and KOH, you can find the number of moles of HBr present in the sample. Finally, divide the moles of HBr by the volume of the sample (12.0 mL) to obtain the concentration of HBr.
What is the concentration of a HBr solution in 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?
Balanced equation. KOH + HBr -> KBr + H2O everything is one to one, so... Molarity = moles of solute/liters of solution ( change ml to liters ) 0.25 M KOH = moles KOH/0.015 liters = 0.00375 moles of KOH this is as many moles that you have of HBr, so... Molarity of HBr = 0.00375 moles/0.012 liters = a concentration of HBr that is 0.31 M
KBr a strong or weak base?
KBr is not a base, but a salt formed by the combination of the strong base KOH and the strong acid HBr. It is considered a neutral salt since it does not significantly contribute to the pH of a solution.
What are the numbers for equation koh hbr equals kbr h2o?
The equation you mentioned is: KOH + HBr → KBr + H2O. This is a neutralization reaction between potassium hydroxide and hydrobromic acid to form potassium bromide and water.
A 76.0ml volume of 0.25m HBr is titrated with 0.50m KOH calculate the pH after addition of 38.0ml of KOH?
To calculate the pH after the addition of KOH, we need to determine the limiting reactant first. The limiting reactant will be the one that is completely consumed, in this case, HBr. The moles of HBr initially present can be calculated and then subtract the moles of KOH added to find the remaining HBr moles. Finally, calculate the concentration of HBr and find the pH using the concentration and dissociation constant of the acid.
What salt forms when you combine HBr and KOH?
When you combine HBr (hydrobromic acid) and KOH (potassium hydroxide), you will form potassium bromide (KBr) and water. This reaction is a neutralization reaction where the H+ ion from the acid combines with the OH- ion from the base to form water, while the remaining ions (K+ and Br-) form the salt potassium bromide.
Is KOH HCI H2O a balanced equation?
NO!!! It is a neutralisation reaction. Reason it produces water (pH =7) KOH + HBr = KBr + H2O KBr (Potassium bromide) is a (chemical) salt. Remember the the empirical acid equations. Acid + Alkali = Salt + water Acid + Base = Salt + water Acid + metal = Salt + hydrogen Acid + carbonate = Salt + Water + Carbon dioxide. NB Acid formulas are always writen as 'HA'. Where 'A' is the anion. Alkali formulkas are always written as 'MOH'. Where 'M' is the metal cation. NNB Notice the positions of the 'H' in these formulas.
What salt is produced from KOH plus pentanoic acid?
The salt produced from the reaction between KOH (potassium hydroxide) and pentanoic acid is potassium pentanoate. This salt is formed by the neutralization reaction between the potassium ion from KOH and the pentanoate ion from pentanoic acid.
What is formed when HCl reacts with KOH?
When hydrochloric acid (HCl) reacts with potassium hydroxide (KOH), potassium chloride (KCl) and water (H2O) are formed. The reaction is a neutralization reaction that produces a salt and water.
Is KNO3 a base acid or salt?
KNO3 is a salt, specifically potassium nitrate. It is formed by the reaction of a strong acid (HNO3) with a strong base (KOH), resulting in a neutral salt.
What salt results from the neutralization of phosphoric acid with potassium hydroxide?
The salt formed from the neutralization of phosphoric acid (H3PO4) with potassium hydroxide (KOH) is potassium phosphate (K3PO4).
