I think you lost some formatting there.
Na+ is isoelectronic with neon, if that's what you were trying to ask.
When sulfur forms a negative ion, it gains two electrons to achieve a full outer electron shell, making it have the same electron configuration as argon.
Bromine is a non-metal element and tends to gain an electron to achieve a stable electron configuration. Therefore, it has a high ionic character when it forms an ion by accepting an electron to become a bromide ion (Br-).
The element fluorine typically forms one single bond because it has seven valence electrons and needs one more electron to complete its octet and become stable.
it becomes an ion. an ion of any element has the same number of protons but different number of electrons. an ion can be of two types. cation and anion. cation is positive i.e. one less electron and an anion is negative, i.e. one more electron. so that's the answer to your original question. if an electron is added, the atom of the element becomes negatively charged.
The element with an electron configuration of Xe 4f14 corresponds to the element Gadolinium (Gd) with atomic number 64. When it forms a 4+ ion, it loses its 4 outer shell electrons, ending up with a stable electron configuration.
because justin is a proton and jere is a electron which forms a harrison
Hydrogen is the element that can form both positive (H+) and negative (H-) ions. When hydrogen gains an electron, it forms a negative ion, and when it loses an electron, it forms a positive ion.
No, iodine is not a cation. Iodine is a non-metal halogen element that typically forms an anion in chemical reactions by gaining an electron to achieve a stable electron configuration.
When sulfur forms a negative ion, it gains two electrons to achieve a full outer electron shell, making it have the same electron configuration as argon.
Bromine is a non-metal element and tends to gain an electron to achieve a stable electron configuration. Therefore, it has a high ionic character when it forms an ion by accepting an electron to become a bromide ion (Br-).
The element fluorine typically forms one single bond because it has seven valence electrons and needs one more electron to complete its octet and become stable.
Potassium is a Group I element (group 1) and therefore LOSES 1 electron to achieve full outer shells and become an ion.
it becomes an ion. an ion of any element has the same number of protons but different number of electrons. an ion can be of two types. cation and anion. cation is positive i.e. one less electron and an anion is negative, i.e. one more electron. so that's the answer to your original question. if an electron is added, the atom of the element becomes negatively charged.
The element with an electron configuration of Xe 4f14 corresponds to the element Gadolinium (Gd) with atomic number 64. When it forms a 4+ ion, it loses its 4 outer shell electrons, ending up with a stable electron configuration.
An element that forms an anion gains electrons to achieve a full outer electron shell, resulting in a negative charge. Anions are generally larger in size compared to their corresponding neutral atoms due to the addition of extra electrons. These anions tend to have higher electron affinity and may participate in ionic bonding with cations to form compounds.
Rhodium (Rh) forms a 3 plus ion that has the electron configuration Kr4d6. Rhodium has oxidation states of 2,3 and 4, so it can loan out 2, 3 or 4 electrons depending on the circumstances of a chemical reaction.
This is Beta decay.