When iron (II) sulfate is put into water, it dissolves to form Fe2+ ions and SO4 2- ions. The chemical equation is: FeSO4 (s) → Fe2+ (aq) + SO4 2- (aq).
Write the reaction when potassium sulfide is put into water:
When an iron nail is placed in a copper sulfate solution, a single displacement reaction occurs. The iron will displace the copper in the solution, forming iron sulfate and depositing copper on the nail, causing it to turn a brownish color due to the presence of copper.
If iron is put in water and oxygen is present the following reaction will happen. 4 Fe + 3 O2 + 6 H2O -> 4 Fe(OH)3 This combination reaction results in iron hydroxide which is basically corroded or rusted iron.
When magnesium and iron are put together in water, a redox reaction can occur where the magnesium acts as the reducing agent and the iron acts as the oxidizing agent. This reaction can lead to the formation of magnesium oxide (MgO) along with the release of hydrogen gas.
Pouring water on it because when it is heated it turns to an endothermic reaction and the hydrated part is boiled put of the compound it is then Anhydrous copper sulphate. When you add water it is hydrated again and this is an exothermic reaction. Which can get extremely hot so don't pour it on your hand and then hydrate it.
Write the reaction when potassium sulfide is put into water:
This compound is soluble in water.
When an iron nail is placed in a copper sulfate solution, a single displacement reaction occurs. The iron will displace the copper in the solution, forming iron sulfate and depositing copper on the nail, causing it to turn a brownish color due to the presence of copper.
Iron (II) sulfate is the correct name for this compound. The Fe ion has a charge of 2 and so does the sulfate ion, so there is no subscript after them.
Any reaction occur when gold is put in copper sulfate.
When cobalt(II) sulfate is added to water, it dissociates into its ions. The formula for cobalt(II) sulfate is CoSO4, and when it is added to water, it dissociates into Co^2+ (cobalt ion) and SO4^2- (sulfate ion).
nothing will happen as i have done this experiment. I think it is because iron is more reactive than copper, so the copper can't take away the sulphate. but if you added the iron to a copper sulphate solution the product would be iron sulphate this reaction is called displacment. David corrected by hari
If iron is put in water and oxygen is present the following reaction will happen. 4 Fe + 3 O2 + 6 H2O -> 4 Fe(OH)3 This combination reaction results in iron hydroxide which is basically corroded or rusted iron.
iron(Fe) being more reactive than Copper(Cu) displaces Cu from copper sulphate (CuSO4). Thus, the following equation is derived:Fe + CuSO4 -----> FeSO4 + CuOBSERVATIONS-1. reddish-brown deposit on the surface of nail2. surface of the nail is found corroded3. the blue solution turns light green
When magnesium and iron are put together in water, a redox reaction can occur where the magnesium acts as the reducing agent and the iron acts as the oxidizing agent. This reaction can lead to the formation of magnesium oxide (MgO) along with the release of hydrogen gas.
Pouring water on it because when it is heated it turns to an endothermic reaction and the hydrated part is boiled put of the compound it is then Anhydrous copper sulphate. When you add water it is hydrated again and this is an exothermic reaction. Which can get extremely hot so don't pour it on your hand and then hydrate it.
Yes. Iron is more reactive than copper, so will displace it from a compound. If you put a piece of iron into copper sulfate solution, it will be soon coated with a deposit of orangey red copper.CuSO4 + Fe --> FeSO4 + Cu