Yes. Iron is more reactive than copper, so will displace it from a compound. If you put a piece of iron into copper sulfate solution, it will be soon coated with a deposit of orangey red copper.CuSO4 + Fe --> FeSO4 + Cu
The reaction between aluminum foil and copper(II) sulfate results in the displacement of copper by aluminum, forming aluminum sulfate and copper metal as products. The balanced chemical equation for this reaction is: 3CuSO4 + 2Al -> Al2(SO4)3 + 3Cu.
The balanced equation for the reaction between aluminum and copper (II) sulfate is: 2Al(s) + 3CuSO₄(aq) -> Al₂(SO₄)₃(aq) + 3Cu(s).
Copper sulfate has CuSO4 as its formula. Copper sulfate is also written copper (II) sulfate.
Nothing will happen. Displacement reaction only happens when the element is more reactive than the salt solution. An example will be the otherwise. If you put aluminum metal into a solution of Copper (II) Sulfate. The aluminum metal will displace copper metal and you will have a solution of Aluminum Sulfate and copper metal. As long the element you put into the salt solution is more reactive than the cation of the solution, it will displace the metal.
Copper(II) sulfate
The reaction of aluminum with copper II sulfate solution is a redox reaction. Aluminum displaces copper from the copper II ion in the copper sulfate solution, forming aluminum sulfate and copper metal.
To find the amount of copper (II) sulfate needed to react with 0.48 mol of aluminum (III) sulfate, start by writing a balanced chemical equation for the reaction between the two salts. From the balanced equation, determine the molar ratio between copper (II) sulfate and aluminum (III) sulfate. Then, use this ratio to calculate the amount of copper (II) sulfate needed to produce 0.48 mol of aluminum (III) sulfate.
The reaction between aluminum foil and copper(II) sulfate results in the displacement of copper by aluminum, forming aluminum sulfate and copper metal as products. The balanced chemical equation for this reaction is: 3CuSO4 + 2Al -> Al2(SO4)3 + 3Cu.
Aluminum metal can react with a solution of copper(II) sulfate (CuSO4) to displace copper metal and form aluminum sulfate. This is a single displacement reaction where aluminum replaces copper in the compound.
The balanced equation for the reaction between aluminum and copper(II) sulfate is: 2Al + 3CuSO4 -> 3Cu + Al2(SO4)3
When copper (II) sulfate reacts with silver nitrate, a white precipitate of silver sulfate is formed. Copper (II) ions from copper (II) sulfate react with nitrate ions from silver nitrate to form a soluble salt.
When sulfuric acid and copper (II) oxide react, copper (II) sulfate and water are produced. The balanced chemical equation for this reaction is: H2SO4 + CuO -> CuSO4 + H2O.
Sugar donates electrons that reduce blue copper (II) sulfate to orange copper (I) oxide.
Copper(II) sulfate and lead(II) nitrate react to form insoluble lead(II) sulfate, which precipitates out of solution. This reaction is a double displacement reaction that occurs when solutions of the two salts are combined.
The balanced equation for the reaction between aluminum and copper (II) sulfate is: 2Al(s) + 3CuSO₄(aq) -> Al₂(SO₄)₃(aq) + 3Cu(s).
Yes, sodium hydroxide can react with copper to form copper(II) hydroxide. When sodium hydroxide is added to a solution containing copper ions, a blue precipitate of copper(II) hydroxide is formed.
When iron(III) reacts with copper sulfate, a displacement reaction occurs where iron displaces copper from copper sulfate. This results in iron(II) sulfate and copper being produced as products. The iron displaces copper because it is higher in the reactivity series.