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In order to determine the polarity of the bond we must first look at the difference of electronegativity.

Below are the values of electronegativity:

Chlorine: 3.0

Iodine: 2.5

Bromine: 2.8

Fluorine: 4.0

Now we look at the difference (subtract the lower number from the higher number):

Cl-Cl=0

Br-I=0.3

F-I=1.5

F-Cl=1.0

Now that we have the difference of electronegativity, we can examine the evidence. Keep in mind that the higher the number, the more polar the bond will be. In this case the most polar bond would be the Flourine-Iodine bond as it has a difference of electronegativity of 1.5, meaning that it is extremely polar.

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