2Cl
There are 6 atoms in 3Cl2. Each Cl2 molecule consists of 2 Cl atoms, so when you have 3 molecules of Cl2, you have a total of 6 Cl atoms.
2253kJ/mol Calculation below Ca(2+) + 2 Cl | 242 | Ca(2+) + Cl2 | | | 348.7 * 2 | 1145 2 Cl(-) + Ca(2+) | | Ca(+) + Cl2 | | 590 | Ca(g) + Cl2(g) | 2253 | 178 | Ca(s) + Cl2(g) | | 795 | CaCl2(s)------------
It is:2Na(s) + Cl2(g) → 2NaCl(s)(But remember in exams you should know this kind of method) Peace out, add me on BBM its:12b6a7d9
The reaction is:Cl2 + 2 Ki = 2 KCl + I2
The coefficient for Cl₂ is 1. If not written explicitly in a chemical equation, a coefficient of 1 is understood to be present.
-1, and since there is two, -2.
Cl2 everyone it is not that hard, 2 x chlorine is Cl2
There are 6 atoms in 3Cl2. Each Cl2 molecule consists of 2 Cl atoms, so when you have 3 molecules of Cl2, you have a total of 6 Cl atoms.
To balance the equation Cu + Cl2 → CuCl2, you need to make sure there are the same number of atoms on each side: 2 Cu atoms on the left, 2 Cl atoms in CuCl2, and 2 Cl atoms in Cl2. So, the balanced equation is Cu + Cl2 → CuCl2.
2253kJ/mol Calculation below Ca(2+) + 2 Cl | 242 | Ca(2+) + Cl2 | | | 348.7 * 2 | 1145 2 Cl(-) + Ca(2+) | | Ca(+) + Cl2 | | 590 | Ca(g) + Cl2(g) | 2253 | 178 | Ca(s) + Cl2(g) | | 795 | CaCl2(s)------------
2Fe+3Cl2------>2FeCl3
It is:2Na(s) + Cl2(g) → 2NaCl(s)(But remember in exams you should know this kind of method) Peace out, add me on BBM its:12b6a7d9
The reaction is:Cl2 + 2 Ki = 2 KCl + I2
The coefficient for Cl₂ is 1. If not written explicitly in a chemical equation, a coefficient of 1 is understood to be present.
The chemical reaction between 2 mol of Cl2 and Br2 forms 2 mol of ClBr3, a molecule known as chlorine bromide. The balanced chemical equation for this reaction is: 2 Cl2 + Br2 → 2 ClBr3.
The correct symbol is Cl2 as gases al ways have 2 atoms.
The reason for this is that one molecule of Cl2 will have 2 atoms of Cl, joined together by a bond. This means that since 1 mole is 6.022 e23 times 2 atoms/molecule =1.204 e24 Cl atoms.