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What is the nuclear equation for the alpha decay of 242 Pu?
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
What is the alpha decay of calcium 42 equation?
There is no equation. Calcium-42 is stable and does not decay. Calcium is also much to light for alpha decay, which requires elements heavier than nickel, so no isotope of calcium undergoes alpha decay.
Ype the letter that represents the formula that will balance this beta decay equation?
An alpha decay equation consists of the nucleus of an atom splitting into two parts: an alpha particle (He atom) and the resulting atom. To balance this equation, make sure that the amount of protons and neutrons are even on both sides.
What is the nuclear equation of the decay of uranium 238?
A:Uranium - 238 --> Pb - 206 + Alpha + Beta note this is a simplified over all reaction, the actual process involves around 15 steps...A:The equation for the alpha decay of 238U is: 92238U --> 90234Th + 24HeThe alpha particle is represented as an He nucleus.
Plutonium-238 decomposes by emitting a particle what is the other product of this decomposition 238 pu 94?
Plutonium 238 is an alpha emitter; the decay product is uranium 234.
What is the nuclear decay equation for plutonium 239?
The first step is an alpha decay to (guess what!) uranium 235. You can probably take it from there.
What is the nuclear equation for the alpha decay of 242 Pu?
The nuclear equation for the alpha decay of 242Pu is: ^24294Pu -> ^23892U + ^4He2 This equation shows that the nucleus of 242Pu decays into a nucleus of 238U and an alpha particle, which is a helium-4 nucleus.
What is the nuclear decay equation for protactinium-231?
The equation for the alpha decay of 222Rn is: 86222Rn --> 84218Po + 24He Where He represents the alpha particle, which can also be viewed as a Helium nucleus.
What is the product of alpha decay?
plutonium-239
To what does plutonium-239 decay when it loses an alpha particle?
Yes, plutonium-239 emits alpha particles by decay.
What is the nuclear decay equation for an example of alpha decay?
There are a number of radioactive isotopes of copper, choosing 66Cu as on that undergoes negative beta decay, the equation is: 2966Cu --> 3066Zn + -10e Where e represents the beta particle, which can also be viewed as an electron.
What is the nuclear equation for the decay of radium 226?
The equation for the alpha decay of 226Ra: 88226Ra --> 86222Rn + 24He The alpha particle is represented as a helium (He) nucleus.
What is the nuclear decay equation for iridium 174?
There are two ways 174Ir can decay, alpha and positive beta, so there are two different equations. The equation for the alpha decay of 174Ir is: 77174Ir --> 75170Re + 24He representing the alpha particle as a helium nucleus. The equation for the beta+ decay of 174Ir is: 77174Ir --> 76174Os + 10e + ve wher 10e represents a positive beta particle or positron.
Which nuclear reaction is classified as alpha decay?
The equation for the alpha decay of 210Po is:84210Po --> 82206Pb + 24He where He represents the alpha particle, which can also be viewed as a Helium nucleus.
What is the nuclear equation for the decay of Po210 if it undergoes 2 alpha decay then a beta decay followed by another alpha decay.?
The nuclear equation for the decay of Po-210 undergoing 2 alpha decays followed by a beta decay and another alpha decay is: Po-210 -> Pb-206 + 4 He-4 + 2 e-1 + 2 v This equation represents the series of decays that result in the transformation of Po-210 into Pb-206, with the emission of two helium nuclei (alpha particles), two electrons, and two neutrinos.
What particles does plutonium give off?
Plutonium is especially an alpha particles emitter.
Which equation correctly represents the alpha decay of polonium 214?
The correct equation for the alpha decay of Polonium-214 is: 218/84Po -> 214/82Pb + 4/2He This shows the decay of Polonium-214 into Lead-214 and a Helium nucleus, where the atomic number and mass numbers are conserved.
