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How many moles of Ag contain 4.4910e23 atoms Ag?
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
How many ag atoms are there in 0.0001 grams of Ag.Molar mass of Ag is 108 gram per mole?
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
What species is reduced in the reaction Fe AgNO3 FeNO33 Ag?
Ag- from Mav student D
How many atoms in AgI?
One formula unit of AgI contains one atom of silver (Ag) and one atom of iodine (I), so there are a total of two atoms in AgI.
What is the oxidizing agent in the reaction Fe AgNO3 FeNO33 Ag?
AgNO3
How many moles of Ag contain 4.4910e23 atoms Ag?
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
How many Ag atoms are there in a 88.1 gram sample of Ag?
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
How many grams are therein 2.31024 atoms of silver?
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
How many ag atoms are there in 0.0001 grams of Ag.Molar mass of Ag is 108 gram per mole?
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
How many mols are there in 5.42x10 to the 24 of atoms Ag?
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
How many moles of Ag contains 4.591025 atom of Ag?
Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------
How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?
The answer is 6,31 moles Ag.
How many moles of Ag in 8.9 x 1024 atoms Ag?
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
How many moles of Ag contains 4.59x10 to the power of 25 atoms of Ag?
76.2 mol Ag
How many atoms are in 1 mole of Ag?
There are 6.022 x 10^23 atoms in 1 mole of silver (Ag) as per Avogadro's number.
What species is reduced in the reaction Fe AgNO3 FeNO33 Ag?
Ag- from Mav student D
Which has more atom 70g of mg or 10g of ag?
Inder to find this out, you divide the numbers of grams you have by the amount of grams it takes to make one mole of that element (6.022 x 10^23) and then multiply by Avigadros number (6.022 x 10^23). That should tell you how many atoms are in the amount of grams you have. See, Avigadros number is the amount of atoms in one mole of every element, so you can use that to figure out about how many atoms are in any given element.
