First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
1 mole Ag = 6 x 10^23 atoms = 107.87g. ? atoms = 1.6g by simple proportion it follows that: 1.6 x 6 x 10^23 / 107.87 = ...
76.2 mol Ag
0.050 moles silver (6.022 X 1023/1 mole Ag) = 3.01 X 1022 atoms of silver --------------------------------------
2.80x10^24 atoms x 1 mole/6.022x10^23 atoms = .465x10^1 mole = 4.65
1 mole Ag = 6.022 x 1023 atoms Ag 4.4910 x 1023 atoms Ag x 1 mole Ag/6.022 x 1023 atoms Ag = 0.7468 mole Ag
10.8 grams silver (1 mole Ag/107.9 grams)(6.022 X 1023/1 mole Ag) = 6.03 X 1022 atoms of silver =====================
Using your molar mass. 0.0001 grams silver (1 mole Ag/108 grams)(6.022 X 1023/1 mole Ag) = 5.58 X 1017 atoms of silver =====================
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
4.55 moles AgNO3 (1 mole Ag/1 mole NO3)(6.022 X 10^23/1 mole Ag) = 2.74 X 10^24 atoms of silver
3.76 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) 2.10 X 10^22 atoms of silver ---------------------------------------
3.68 grams silver (1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.05 X 10^22 atoms of silver -----------------------------------------
1 mol of Ag and 1 mol of Au can be said to contain the same amount of atoms of each element.
0.84 lb silver (454 grams/1 lb)(1 mole Ag/107.9 grams)(6.022 X 10^23/1 mole Ag) = 2.1 X 10^24 atoms of silver
1 atom of silver (Ag)= 107.87 amu 1 mole of a substance is 6.022 x 1023 of that substance. 1 MOLE of silver (Ag)= 107.87 grams So, in the three step formula: 1 atom Ag x 1 mole Ag/6.022 x 1023 atoms Ag ≈ 1.660577881 x 10-24 Mole Ag 1.660577881 x10-24 Mole Ag x 107.87 g Ag/ 1 mole Ag ≈ 1.79126536 x 10-22 g. Ag Or, to conserve significant figures, 1.7913 x 10-22 g. Ag (because 1 mole is definite, we don't count its significant figures
1 mole Ag = 6 x 10^23 atoms = 107.87g. ? atoms = 1.6g by simple proportion it follows that: 1.6 x 6 x 10^23 / 107.87 = ...
76.2 mol Ag