4.55 moles AgNO3 (1 mole Ag/1 mole NO3)(6.022 X 10^23/1 mole Ag)
= 2.74 X 10^24 atoms of silver
moles
3 moles of Ca would have 1.806 × 10^24 atoms.
AgNO3
1 mole of iron atoms has the greatest mass - 55,845 g.
15.8 moles Cu x 6.02x10^23 atoms/mole = 9.51x10^22 atoms. There are no molecules in the element Cu (copper). Molecules are found when there are two or more atoms bound together, such as in H2 gas or H2O, etc.
Balanced equation first! AgNO3 + NaCl -> AgCl + NaNO3 all one to one, get moles AgNO3 3.82 moles NaCl (1 mole AgNO3/1 mole NaCl) = 3.82 moles AgNO3 ------------------------------- Molarity = moles of solute/Liters of solution 0.117 M AgNO3 = 3.82 moles AgNO3/Liters Liters = 3.82/0.117 = 32.6 Liters which is 32600 milliliters which is unreasonable; check answer if you can
I assume double displacement reaction. Balanced equation. 3AgNO3 + Na3PO4 -> Ag3PO4 + 3NaNO3 2.00 moles sodium phosphate ( 3 moles AgNO3/1 mole Na3PO4) = 6.00 moles silver nitrate needed =========================
its 125,524,727,836
moles
agno3
AgNO3
One mole of atoms is 6.02x1023 atoms, so 10 moles of any substance would contain 6.02x1024 atoms.
3 moles of Ca would have 1.806 × 10^24 atoms.
AgNO3
One googol of atoms would be 10100 atoms or 1.66 × 1076 moles.
This is an incomplete question for several reasons. Iron bromide can be FeBr2 or FeBr3 and this will influence the answer. Also, in order to precipitate silver bromide, one would add silver nitrate, but it isn't stated how much silver nitrate is used. Assuming FeBr2 is used, and there is excess AgNO3, then .... 2AgNO3 + FeBr2 ----> 2AgBr(s) + Fe(NO3) moles FeBr2 = 2.96 g x 1 mol/216 g = 0.0137 moles moles AgBr produced = 2 x 0.0137 = 0.0274 moles mass AgBr produced = 0.0274 moles x 188 g/mole = 5.15 grams <---answer
the compound is chemically AgNO3, by mass, that would mean silver nitrate is 63% elemental silver. By volume, silver is denser than nitrogen or oxygen and would be less than 63%.