One mole of atoms is 6.02x1023 atoms, so 10 moles of any substance would contain 6.02x1024 atoms.
0.188 moles Na (6.022 X 10^23/1 mole Na) = 1.13 X 10^23 atoms of sodium
1.56 X 10^21 atoms of sodium ( 1 mole Na/6.022 X 10^23) = 0.00259 moles sodium or 2.59 X 10^-3 moles sodium
3.7 moles sodium (6.022 X 10^23/1 mole Na) = 2.2 X 10^24 atoms of sodium
1 mol = 6,022x1023 atoms/molecules (Avogadro's number) 0,615 x NA (Avogadro's number) = 3,703 53.1023 atoms of C-13
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
0.188 moles Na (6.022 X 10^23/1 mole Na) = 1.13 X 10^23 atoms of sodium
In a mole there is 6.022 x 1023 atoms. In two moles there are twice that amount.
0.013089701
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
0.25 x 6.022 x 10^23=1.05055 x10^23
Quite a few. 6.32 X 10^25 atoms sodium (1 mole Na/6.022 X 10^23) = 105 moles of sodium
Atomic Mass of Na: 23.0 grams1.50 moles × (6.02 × 1023 atoms) = 9.03 × 1023atoms
1.56 X 10^21 atoms of sodium ( 1 mole Na/6.022 X 10^23) = 0.00259 moles sodium or 2.59 X 10^-3 moles sodium
3.7 moles sodium (6.022 X 10^23/1 mole Na) = 2.2 X 10^24 atoms of sodium
6.02x10^23 is Avogadro's number is it represents the number of atoms in a mole of anything. So, the answer would be 1 mole of Na contains 6.02x10^23 atoms of Na.
The answer is NA x 3,5 = 21,0775.10e+23.
1 mol = 6,022x1023 atoms/molecules (Avogadro's number) 0,615 x NA (Avogadro's number) = 3,703 53.1023 atoms of C-13