One mole is 6.02*1023 atoms. So to find out how many moles are in 1.43*1024 , it's as simple as dividing the second number by the first. This results in 2.38 moles (rounded to significant figures)
0.21705 moles. There are 22.9898 grams sodium in 1 mole.
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
Since Na2O is a 1:1 ratio with Na, if 2.80 moles of Na react, 2.80 moles of Na2O will be produced. To convert moles to grams, we use the molar mass of Na2O (61.98 g/mol) to find that 2.80 moles of Na2O is equal to 2.80 moles * 61.98 g/mol = 173.50 grams of Na2O.
To find the number of grams in 0.350 moles of Na, you need to multiply the number of moles by the molar mass of Na. The molar mass of Na is 22.99 g/mol. So, 0.350 moles of Na * 22.99 g/mol = 8.0465 grams of Na.
The answer is 0,25 moles.
0.013089701
To find the number of moles of Na in 42 grams, we can use the molar mass of Na, which is approximately 23 grams/mol. First, calculate the number of moles by dividing the given mass by the molar mass: 42 grams / 23 grams/mol = 1.83 moles of Na.
When sodium oxide (Na₂O) decomposes, it breaks down into its constituent elements: sodium (Na) and oxygen (O). The balanced chemical equation for the decomposition is 2 Na₂O → 4 Na + O₂. From this equation, 1 mole of Na₂O produces 2 moles of Na. Therefore, if a chemist has 1.87 moles of Na₂O, it will produce 1.87 moles × 2 = 3.74 moles of Na.
0.21705 moles. There are 22.9898 grams sodium in 1 mole.
Using the equation 2Na + 2HCl -> 2NaCl + H2, we can see that 2 moles of Na react with 2 moles of HCl to produce 1 mole of H2. Calculate moles of Na: 25g Na * 1 mol Na / 23g Na = 1.09 mol Na. Since the reaction is with excess HCl, the number of moles of H2 produced will be half the number of moles of Na, so it will be 0.545 moles of H2.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
0.188 moles Na (6.022 X 10^23/1 mole Na) = 1.13 X 10^23 atoms of sodium