57,848 g Na2O
6 Na + 2 O2 = 2 Na2O + Na2O2
46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.
To find the grams of oxygen in 765g of Na2O, we first need to calculate the molar mass of Na2O. This can be done by adding the atomic masses of sodium and oxygen. The molar mass of Na2O is 61.98 g/mol. Since there are 2 oxygen atoms in 1 molecule of Na2O, the molar mass of oxygen is 32 g/mol. So the mass of oxygen in 765 g of Na2O would be (2*32)/61.98 * 765g.
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
The reactants are always on the left hand side, so H2 and O2.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
The balanced equation for the reaction is: 4 Na + O2 -> 2 Na2O. From the equation, 4 moles of sodium will react to form 2 moles of sodium oxide. Calculate the molar mass of Na2O (sodium oxide) to find out how many grams will be formed.
46 grams of sodium is 2 moles. 2 mol of sodium forms 1 mol of sodium oxide. So it makes 62 g of sodium oxide.
To find the grams of oxygen in 765g of Na2O, we first need to calculate the molar mass of Na2O. This can be done by adding the atomic masses of sodium and oxygen. The molar mass of Na2O is 61.98 g/mol. Since there are 2 oxygen atoms in 1 molecule of Na2O, the molar mass of oxygen is 32 g/mol. So the mass of oxygen in 765 g of Na2O would be (2*32)/61.98 * 765g.
62 grams a+
Na2O or sodium oxide is an ionic compound.The formula mass of Na2O is 2(23.0) + 16 = 62.0 Amount of Na2O = 6.2/62.0 = 0.1mol In each formula unit of Na2O there are two singly positively charged Na+ ions. So, amount of sodium ions = 0.2 moles.
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
Oxygen react with sodium: the two oxides are Na2O and Na2O2.
1 mole of Sodium Chloride weighs 58.5 grams (1 mole is the same as the molecular weight of a compound. The molecular mass of Sodium Chloride- NaCl is 23 [Na atomic mass] + 35.5 [Cl atomic mass] which is equal to 58.5 grams).Thus 10 moles would weigh 10x58.5 grams = 585 grams.The answer is 585 grams.
The reactants are always on the left hand side, so H2 and O2.
When sodium carbonate (Na2CO3) decomposes, it forms sodium oxide (Na2O) and carbon dioxide (CO2) gas as byproducts.
The reaction between sodium and water will produce sodium hydroxide and hydrogen. The reaction will also produce energy in the form of light and heat. This heat will ignite the remaining sodium, followed by the ignition of the hydrogen produced (hydrogen will react with the oxygen in the surrounding air). The result will be an explosion.