The reaction between sodium and water will produce sodium hydroxide and hydrogen. The reaction will also produce energy in the form of light and heat. This heat will ignite the remaining sodium, followed by the ignition of the hydrogen produced (hydrogen will react with the oxygen in the surrounding air). The result will be an explosion.
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
Na2O + H2SO4 ---> Na2SO4 + H2O This is balanced, and is called a neutralization reaction. All neutralization reactions involve a base, an acid, and have a result of a salt and water.
When sodium oxide (Na2O) reacts with water (H2O), it forms sodium hydroxide (NaOH), which is a strong base. The reaction between Na2O and H2O produces hydroxide ions (OH-) in solution, increasing the pH and making it basic.
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
Na2O + H2SO4 ---> Na2SO4 + H2O This is balanced, and is called a neutralization reaction. All neutralization reactions involve a base, an acid, and have a result of a salt and water.
When sodium oxide (Na2O) reacts with water (H2O), it forms sodium hydroxide (NaOH), which is a strong base. The reaction between Na2O and H2O produces hydroxide ions (OH-) in solution, increasing the pH and making it basic.
The reaction between sodium oxide (Na2O) and water (H2O) forms sodium hydroxide (NaOH). The chemical equation for this reaction is: Na2O + H2O -> 2NaOH
one is an oxide while the other is a hydroxide
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
At very high temperature NaOH is decomposed and Na2O fumes are emited.The reaction is:2 NaOH = Na2O = H2O
Na2O + H2O -> 2NaOH
Na2O+H2O--->2NaOH
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
The reactants are always on the left hand side, so H2 and O2.
The chemical equation is:2 NaHCO3---------------------Na2O + 2 CO2 + H2O