one is an oxide while the other is a hydroxide
The balanced equation for Na2O + H2O → 2 NaOH is: Na2O + H2O → 2 NaOH
When sodium oxide (Na2O) reacts with water (H2O), it forms sodium hydroxide (NaOH), which is a strong base. The reaction between Na2O and H2O produces hydroxide ions (OH-) in solution, increasing the pH and making it basic.
The reaction between sodium oxide (Na2O) and water (H2O) forms sodium hydroxide (NaOH). The chemical equation for this reaction is: Na2O + H2O -> 2NaOH
The balanced chemical equation for the reaction between sodium oxide (Na2O) and water (H2O) is: 2Na2O + 2H2O -> 4NaOH From the equation, it can be seen that 2 moles of Na2O react with 2 moles of H2O to produce 4 moles of NaOH. Therefore, 42.0 moles of water would react with 21.0 moles of sodium oxide (Na2O).
At very high temperature NaOH is decomposed and Na2O fumes are emited.The reaction is:2 NaOH = Na2O = H2O
Na2O + H2SO4 ---> Na2SO4 + H2O This is balanced, and is called a neutralization reaction. All neutralization reactions involve a base, an acid, and have a result of a salt and water.
Na2O + H2O -> 2NaOH
Na2O+H2O--->2NaOH
BaCl2 + Na2CO3 -> BaCO3 + 2NaCl
The reactants are always on the left hand side, so H2 and O2.
The chemical equation is:2 NaHCO3---------------------Na2O + 2 CO2 + H2O
When sodium oxide reacts with water, it undergoes a chemical reaction to form sodium hydroxide. This reaction involves the hydration of sodium oxide, which results in the formation of sodium hydroxide as a product. The chemical equation for this reaction is: Na2O + H2O → 2NaOH.