0.21705 moles. There are 22.9898 grams sodium in 1 mole.
To find the number of grams in 0.350 moles of Na, you need to multiply the number of moles by the molar mass of Na. The molar mass of Na is 22.99 g/mol. So, 0.350 moles of Na * 22.99 g/mol = 8.0465 grams of Na.
Since Na2O is a 1:1 ratio with Na, if 2.80 moles of Na react, 2.80 moles of Na2O will be produced. To convert moles to grams, we use the molar mass of Na2O (61.98 g/mol) to find that 2.80 moles of Na2O is equal to 2.80 moles * 61.98 g/mol = 173.50 grams of Na2O.
M.W. of the given compound is 3x23+1x31+4x16=164 in Na3PO4 3 moles of Na+ ions are produces i.e., 1mole weighs 164g contain 3x6.023x10^23 Na+ ions ?5.43g contain = 5.43g x 3 moles Na+ x 6.023x10^23 / 164 g/mol Na+ ions=0.598x10^23
The molar mass of sodium (Na) is 22.99 g/mol. Therefore, the mass of 8 moles of sodium atoms would be 8 moles x 22.99 g/mol = 183.92 grams.
The molar mass of sodium is approximately 23 grams per mole. Therefore, 2 moles of sodium would weigh around 46 grams.
To find the number of moles of Na in 15 g of NaCl, you first need to calculate the molar mass of NaCl, which is 58.44 g/mol. Since Na makes up 39.34% of the molar mass of NaCl, you can calculate the moles of Na as (15 g / 58.44 g/mol) * 0.3934 = 0.255 moles of Na.
To find the number of grams in 0.350 moles of Na, you need to multiply the number of moles by the molar mass of Na. The molar mass of Na is 22.99 g/mol. So, 0.350 moles of Na * 22.99 g/mol = 8.0465 grams of Na.
For this you need the atomic mass of Na. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel.11.5 grams Na / (23.0 grams) = .500 moles Na
Since Na2O is a 1:1 ratio with Na, if 2.80 moles of Na react, 2.80 moles of Na2O will be produced. To convert moles to grams, we use the molar mass of Na2O (61.98 g/mol) to find that 2.80 moles of Na2O is equal to 2.80 moles * 61.98 g/mol = 173.50 grams of Na2O.
To find the number of moles of Na in 42g of Na, you would first calculate the molar mass of Na (sodium is 22.99 g/mol), and then divide the given mass by the molar mass. moles of Na = 42g / 22.99 g/mol ≈ 1.83 moles
To find the grams of sodium in 0.820 moles of Na2SO4, first calculate the molar mass of Na2SO4: 2(Na) + 1(S) + 4(O) = 2(23) + 32 + 4(16) = 142 g/mol. Since each mole of Na2SO4 contains 2 moles of Na atoms, the molar mass of Na in Na2SO4 is 46 g/mol. Therefore, in 0.820 moles of Na2SO4, there are 0.820 moles * 2 moles Na * 46 g/mol = 75.32 grams of sodium.
To determine how many grams of H2 can be produced from the reaction of sodium with water, we first use the balanced chemical equation: 2 Na + 2 H2O → 2 NaOH + H2. The molar mass of sodium (Na) is approximately 23 g/mol, so 72 g of sodium corresponds to about 3.13 moles of Na (72 g / 23 g/mol). According to the equation, 2 moles of Na produce 1 mole of H2, so 3.13 moles of Na will produce about 1.57 moles of H2. Since the molar mass of H2 is about 2 g/mol, this results in approximately 3.14 grams of H2 (1.57 moles × 2 g/mol).
To find the number of moles in 114g of SbCl3, first calculate the molar mass of SbCl3: Sb (121.8 g/mol) + 3Cl (3*35.5 g/mol) = 214.3 g/mol. Next, divide the given mass (114g) by the molar mass to get the number of moles: 114g / 214.3g/mol ≈ 0.532 moles of SbCl3.
M.W. of the given compound is 3x23+1x31+4x16=164 in Na3PO4 3 moles of Na+ ions are produces i.e., 1mole weighs 164g contain 3x6.023x10^23 Na+ ions ?5.43g contain = 5.43g x 3 moles Na+ x 6.023x10^23 / 164 g/mol Na+ ions=0.598x10^23
The molar mass of sodium (Na) is 22.99 g/mol. Therefore, the mass of 8 moles of sodium atoms would be 8 moles x 22.99 g/mol = 183.92 grams.
The molar mass of sodium is approximately 23 grams per mole. Therefore, 2 moles of sodium would weigh around 46 grams.
molar mass Na = 22.99g/mol (atomic weight in grams) 0.0135mol Na x (22.99g/mol) = 0.310g Na