32.7 g x 1 mol/22.99 g = 1.422 mol x 6.022x10^23 molecules/1mol = 8.565 x 10^23 molecules(also called atoms)
0,00132 mol of Na contain 7,94922593124.10e20 atoms.
The number of atoms is 7,596.10e23.
1.8 Mol Na
1.8 moles
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
Molar Mass NaCl is 58.5g, 39.3% Na (5.90g), Molar Mass Na is 23.0g, 5.90/23.0 = 0.256 moles
0.188 moles Na (6.022 X 10^23/1 mole Na) = 1.13 X 10^23 atoms of sodium
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 2.5 moles Na+ and 2.5 moles Cl-, totaling 5 moles of ions altogether.
1.8 moles
as 1 mole of ni trogen = 14g thereforre are 3 moles of nitrogen in 42g, similarly 1 mole of oxygen is = 16g therefore 3*16 =48 g
one
The answer is 0,25 moles.
0.013089701
42g = 1.48oz
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
Balanced equation. 4Na + O2 -> 2Na2O 10 moles Na (2 moles Na2O/4 moles Na) = 5.0 moles Na2O produced
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
Molar Mass NaCl is 58.5g, 39.3% Na (5.90g), Molar Mass Na is 23.0g, 5.90/23.0 = 0.256 moles
0.188 moles Na (6.022 X 10^23/1 mole Na) = 1.13 X 10^23 atoms of sodium
0.21705 moles. There are 22.9898 grams sodium in 1 mole.