0.188 moles Na (6.022 X 10^23/1 mole Na)
= 1.13 X 10^23 atoms of sodium
One mole of atoms is 6.02x1023 atoms, so 10 moles of any substance would contain 6.02x1024 atoms.
3.7 moles sodium (6.022 X 10^23/1 mole Na) = 2.2 X 10^24 atoms of sodium
To find the number of moles of Na in 42g of Na, you would first calculate the molar mass of Na (sodium is 22.99 g/mol), and then divide the given mass by the molar mass. moles of Na = 42g / 22.99 g/mol ≈ 1.83 moles
I cannot answer this question.
4.0 X Avogadro's Number or 2.4 X 1024. (Elemental sodium does not technically have "moles", but its formula mass is considered to be that of a single atom.)
0.013089701
0.125 moles x 6.02x10^23 atoms/mole = 7.53x10^22 atoms
Atomic Mass of Na: 23.0 grams1.50 moles × (6.02 × 1023 atoms) = 9.03 × 1023atoms
In a mole there is 6.022 x 1023 atoms. In two moles there are twice that amount.
One mole of atoms is 6.02x1023 atoms, so 10 moles of any substance would contain 6.02x1024 atoms.
The answer is NA x 3,5 = 21,0775.10e+23.
I assume you mean 10.453x1023 atoms of sodium. 1 mole of anything contains 6.02x1023 representative particles (Avogadro's number), so if you divide the given number of atoms by Avogadro, you get 1.736 moles.
One mole is 6.02*1023 atoms. So to find out how many moles are in 1.43*1024 , it's as simple as dividing the second number by the first. This results in 2.38 moles (rounded to significant figures)
How many atoms of gallium are in 2.85 x 103 g of gallium?
3.7 moles sodium (6.022 X 10^23/1 mole Na) = 2.2 X 10^24 atoms of sodium
To find the number of moles of Na in 42g of Na, you would first calculate the molar mass of Na (sodium is 22.99 g/mol), and then divide the given mass by the molar mass. moles of Na = 42g / 22.99 g/mol ≈ 1.83 moles
0.25 x 6.022 x 10^23=1.05055 x10^23