1 mole Ag = 6 x 10^23 atoms = 107.87g.
? atoms = 1.6g
by simple proportion it follows that:
1.6 x 6 x 10^23 / 107.87 = ...
There are 6.022 x 10^23 atoms in 1 mole of silver (Ag) as per Avogadro's number.
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
In one Ag2O there are 2 'Ag' (silver) atoms and 1 'O' (oxygen) atom: three in total
76.2 mol Ag
A 88,1 gram sample of Ag contain 4,9185.10e23 atoms.
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
That is 3 teaspoons.
The answer is 6,31 moles Ag.
There are 6.022 x 10^23 atoms in 1 mole of silver (Ag) as per Avogadro's number.
5.42 X 10^24 atoms silver ( 1mole Ag/6.022 X 10^23) = 9.00 moles of silver
16 grams = 16,000 mg
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag
One formula unit of AgI contains one atom of silver (Ag) and one atom of iodine (I), so there are a total of two atoms in AgI.
Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------