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How many atoms of sodium na are in 7 mol of sodium answer in units of atoms?
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
How many atoms are there in 1.25 mol of silver?
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
How many atoms are in 62 moles of silver?
1 mole of silver contains 6.022 X 10^23 atoms 62 moles of silver contains 3.73 X 10^25 atoms of silver
How many atoms are present in 80.0 mol of zirconium?
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
How many atoms are in 5 moles of silver?
The answer is: Number of Avogadro x 5 = 30,11070645.1023 atoms.
How many atoms are in 0.250 mol of silver?
The answer is approx. 1,5.10e23 atoms of silver.
How many atoms are present in 0.263 mol of silver?
The amount of moles is also defined as n = N/NA, wheren - amount of molesN - amount of atomsNA - Avogadro constant (approx. 6.02214179×1023 mol-1), thereforeN = n×NA = 0.263×6.02214179×1023 = 1,583823291×1023 atoms.
How many oxygen atoms are in 0.02 mol of silver phosphate?
There are 4 O atoms per molecule Ag3PO4 .In 0.02 mole Ag3PO4 are0.02(mole) * 6.022*10+23(molecules/mole) * 4(atolms/molecule) = 4.8*10+22 atoms Oxygen
How many silver atoms are there in 3.76g of silver?
To calculate the number of silver atoms in 3.76g of silver, you need to use Avogadro's number and the molar mass of silver. The molar mass of silver is 107.87 g/mol. First, calculate the number of moles in 3.76g of silver. Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of silver atoms in that many moles.
How many silver atoms are there in 3.88 g of silver?
To find the number of silver atoms in 3.88 g of silver, you can use the formula: Number of atoms = (mass in grams / molar mass) x Avogadro's number The molar mass of silver is 107.87 g/mol, and Avogadro's number is 6.022 x 10^23 mol^-1. Therefore, there are approximately 8.59 x 10^22 silver atoms in 3.88 g of silver.
What is the number of atoms in 20.5 g silver?
Silver (Ag) has a molar mass of 107.87g/mol, so by dividing 20.5 by its molar mass, you get how many moles of silver atoms there are in that much silver.(20.5gAg)(1mol/107.87g) = 0.190 moles silver atomsNow, 1 mole = 6.02*1023 (Like a dozen = 12, a mole is just a value.) so if you can't answer in moles, just multiply 0.190 moles by 6.02*10230.190 mol*(6.02*1023/1mol)= 1.14*1023 silver atoms
How many atoms of sodium na are in 7 mol of sodium answer in units of atoms?
the constant Mole (mol): 6.02 x 10^23 are how many atoms you have per mol so the answer can be 7 mol atoms or 6.02 x 10^23 atoms per mol x 7 actual answer is 4.214 X10^24 atoms in 7 mol
How many atoms are there in 1.25 mol of silver?
you have m = 12.5g M = 107.9g/mol Na = 6.02x10^23atoms/mol = avagadros number N = ? atoms then the number of moles is n = m/M = N/Na gives N = mNa/M = 12.5*6.02x10^23 / 107.9 = 6.97 x 10^22 atoms
How many moles of silver are in a ring that has 1.1 x 1022 Ag atoms?
To find the number of moles of silver in the ring, you need to divide the number of silver atoms by Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles of silver = 1.1 x 10^22 Ag atoms / 6.022 x 10^23 atoms/mol Calculating this gives approximately 0.018 moles of silver in the ring.
How many silver atoms are there in 3.68 g of silver?
To calculate the number of silver atoms in 3.68 g of silver, first determine the molar mass of silver (Ag) which is 107.87 g/mol. Next, calculate the number of moles of silver in 3.68 g by dividing the mass by the molar mass. Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of silver to atoms.
How many atoms are in 62 moles of silver?
1 mole of silver contains 6.022 X 10^23 atoms 62 moles of silver contains 3.73 X 10^25 atoms of silver
How many atoms are present in 80.0 mol of zirconium?
To determine the number of atoms in 80.0 mol of zirconium, you can use Avogadro's number, which is 6.022 x 10^23 atoms/mol. Multiply 80.0 mol by Avogadro's number to find the total number of atoms in 80.0 mol of zirconium.
