H2CO3 is stronger, meaning that the 1st H+ is easier to remove.
HCO3- is weaker because the 2nd H+ must be removed from a negative ion (which attracts the H+).
Ka= [h+][HCO3-]/[H2CO3]
Hco3- => h2co3
ph=pka+log[A-]/HA A-= HCO3- HA= H2CO3 7.4=6.1+ log A-/HA 1.3=logA-/HA 10^1.3=A-/HA= 19.95 therefore the ratio of concetration is HCO3- is 19.95 to 1 H2CO3 or there is more HCO3
H2CO3 is atype of ionization which depend on two steps as following :H2CO3 H+ + HCO3- HCO3- H+ + CO3-2
You mean,HCO3 - = bicarbonateH2CO3 = carbonic acid and the conjugate of the above base.
Ka= [h+][HCO3-]/[H2CO3]
Hco3- => h2co3
ph=pka+log[A-]/HA A-= HCO3- HA= H2CO3 7.4=6.1+ log A-/HA 1.3=logA-/HA 10^1.3=A-/HA= 19.95 therefore the ratio of concetration is HCO3- is 19.95 to 1 H2CO3 or there is more HCO3
H2CO3 is atype of ionization which depend on two steps as following :H2CO3 H+ + HCO3- HCO3- H+ + CO3-2
You mean,HCO3 - = bicarbonateH2CO3 = carbonic acid and the conjugate of the above base.
I think you mean H+ + HCO3- --> H2CO3
hco3- + h+ <---> h2co3
NaHCO3 ---> Na+(aq) + HCO3-(aq) CH3COOH <--> H+(aq) + CH3COO-(aq) H+ + HCO3- ---> H2CO3 H2CO3 ---> H2O + CO2
The conjugate base of HCO3- (bicarbonate ion) is CO32- (carbonate ion) The conjugate acid of HCO3- (bicarbonate ion) is H2CO3 (carbonic acid)
H2CO3 is Carbonic Acid or HCO3- is Bicarbonate
H2co3+h2o -> h3o+ + hco3-
protein, HCO3-, H2CO3