The formula for the tin four ion is Sn+4
how many proton and electron are in the tin IV ion
A Stannic ion is the ion of Tin(IV). Its formula is Sn4+ . Here tin is in its highest oxidation state of +4. The other ion is Stannous(Sn2+).
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
Purple permanganate ion is reduced and almost decolorized (to Mn(II)) by chloride ion in acid solution. Purple permanganate ion is reduced to green manganate ion by chloride ion in basic solution. In neutral chloride solution, there is no reaction.Source: UW Card Catalog
The formula for the tin four ion is Sn+4
how many proton and electron are in the tin IV ion
A Stannic ion is the ion of Tin(IV). Its formula is Sn4+ . Here tin is in its highest oxidation state of +4. The other ion is Stannous(Sn2+).
According to the periodic table, Sn is the symbol for tin.
Sn(CrO4)2 Tin 4 means that the tin is a cation with a +4 charge. Chromate is a polyatomic ion with the formula (CrO4)-2. Since the tin ion has a +4 charge in this case, and the chromate ion has a -2 charge, there is a 1:2 ratio of tin ions to chromate ions.
Sn4+
Purple permanganate ion is reduced and almost decolorized (to Mn(II)) by chloride ion in acid solution. Purple permanganate ion is reduced to green manganate ion by chloride ion in basic solution. In neutral chloride solution, there is no reaction.Source: UW Card Catalog
If you mean Sn2+ it is known as Tin(II) ion in the stock system or stannous ion in the old naming system.
The tin ion, Sn2+, and the nitrate ion, NO3-.
Tin(IV) = Sn4+Chloride = Cl-Formula = SnCl4
Cu2+
The formula is SnF2.