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PbI2, lead(II) iodide, is an ionic compound. Lead(II) is a metal and iodide is a non-metal, so they typically form ionic bonds.
PbCrO4, which is lead(II) chromate, is a solid under normal conditions. The compound is ionic in nature, consisting of a +2 lead cation and a -2 chromate anion. Ionic compounds are nearly all crystalline solids at room temperature.
Lead (II) iodide (PbI2) is ionic. Lead (Pb) is a metal and iodine (I) is a nonmetal, so they form an ionic bond by transferring electrons. In this compound, lead forms a 2+ cation and iodine forms a 1- anion, resulting in an overall neutral compound.
PbBr2 is an ionic compound because lead (Pb) is a metal and bromine (Br) is a non-metal. Ionic compounds form when a metal reacts with a non-metal, resulting in the transfer of electrons from the metal to the non-metal.
The chemical reaction is: 2 (K+ + I-)(aq) + (Pb2+ + 2 [NO-3])(aq)-----------------2 (K+ + [NO-3]) + PbI2(s)
Yes. It is an ionic compound, and all ionic compounds are crystalline solids at room temperature.
PbI2, lead(II) iodide, is an ionic compound. Lead(II) is a metal and iodide is a non-metal, so they typically form ionic bonds.
PbCrO4, which is lead(II) chromate, is a solid under normal conditions. The compound is ionic in nature, consisting of a +2 lead cation and a -2 chromate anion. Ionic compounds are nearly all crystalline solids at room temperature.
Lead (II) iodide (PbI2) is ionic. Lead (Pb) is a metal and iodine (I) is a nonmetal, so they form an ionic bond by transferring electrons. In this compound, lead forms a 2+ cation and iodine forms a 1- anion, resulting in an overall neutral compound.
PbBr2 is an ionic compound because lead (Pb) is a metal and bromine (Br) is a non-metal. Ionic compounds form when a metal reacts with a non-metal, resulting in the transfer of electrons from the metal to the non-metal.
Two: lead and iodine.
The chemical reaction is: 2 (K+ + I-)(aq) + (Pb2+ + 2 [NO-3])(aq)-----------------2 (K+ + [NO-3]) + PbI2(s)
The chemical formula for lead II iodide is PbI2. It is a yellow crystalline compound with a high solubility in water.
This compound is lead iodide.
An example of an insoluble compound formed in a double displacement reaction is a precipitate, such as silver chloride (AgCl) or lead iodide (PbI2). When two soluble ionic compounds react in a double displacement reaction, they may form an insoluble product that precipitates out of solution.
Pb(NO3)2 + 2KI -> PbI2 + 2KNO3.
The compound formed when lead reacts with iodine is lead(II) iodide, with the chemical formula PbI2.